如果在其他选择选项值中选择了选项,我需要提醒。如果选中,则禁用该选项但由于禁用属性而无法插入数据库。所以我只想提醒。
<select class="input_slip_no form-control" name="slip_no[]" id="ID_2_slip_no" required="required">
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_3_slip_no" required="required">
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_4_slip_no" required="required">
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_5_slip_no" required="required">
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
如果选择了其他选择选项,则此更改功能禁用该选项。当我改变警告它不起作用。如何在其他选择选项中选择时仅提醒。
$('.input_slip_no').on('change', function() {
var selected_options = $('.input_slip_no').map(function(){
return this.value
}).get();
$('.input_slip_no option').each(function(index) {
$(this).prop('disabled', $.inArray($(this).val(), selected_options) != -1);
});
});
答案 0 :(得分:3)
这里使用jQuery选择器,如下所示
注意:我已将空元素添加为初始选定值,因为在上面的示例中选择了相同的值。
$('.input_slip_no').change(function(){
var selected = $(this).val();
if(selected) {
var otherSelected = $('.input_slip_no').not($(this)).find('option[value="' + selected + '"]:selected');
if(otherSelected.length > 0) {
alert('Option is already selected');
$(this).val('');
}
}
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_2_slip_no" required="required">
<option value=""></option>
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_3_slip_no" required="required">
<option value=""></option>
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_4_slip_no" required="required">
<option value=""></option>
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
<select class="input_slip_no form-control" name="slip_no[]" id="ID_5_slip_no" required="required">
<option value=""></option>
<option value="SYS0001">SYS0001</option>
<option value="SYS0002">SYS0002</option>
<option value="SYS0003">SYS0003</option>
<option value="SYS0004">SYS0004</option>
<option value="SYS0005">SYS0005</option>
<option value="SYS0006">SYS0006</option>
<option value="SYS0007">SYS0007</option>
<option value="SYS0008">SYS0008</option>
<option value="SYS0009">SYS0009</option>
</select>
&#13;
答案 1 :(得分:0)
请看一下这个链接:
$('.ddControl').change(function(){
for(var i=0;i<$('.ddControl').length;i++){
debugger;
if($(this).attr('id') != $($('.ddControl')[i]).attr('id'))
{
if($(this).val() == $($('.ddControl')[i]).val())
{
alert('Option is already selected');
}
}
}
})