Question

我从UI调用Method，方法需要很长时间才能完成所以它冻结了用户界面并阻止用户知道发生了什么。

我正在尝试更新＆＃39; datagridview＆＃39;的列（状态）在UI上反馈用户，让他知道哪个IP已连接，哪个尚未连接，但正如我在UI冻结之前说的那样，直到方法完成。

其中一个建议是使用线程，我这样做，但我的问题没有解决，所以我做了正确的事情？

    public void PatchUpdates()
    {
        try
        {
            foreach (DataGridViewRow OfficeListRow in DGV_OfficeList.Rows)
            {
                string OfficeIPAddress = OfficeListRow.Cells[3].Value.ToString();

                foreach (DataGridViewRow FileListRow in DGV_FileList.Rows)
                {
                    string SoruceFileNamePath = FileListRow.Cells[4].Value.ToString();
                    string DestinationFileNamePath = @"\\" + OfficeIPAddress + @"\usb1_1\test\" + Path.GetFileName(SoruceFileNamePath);

                    Thread foregroundthread = new Thread(() => CheckOffice(OfficeIPAddress));
                    foregroundthread.Start();

                    //check if connection to remote server is available
                    if (CheckOffice(OfficeIPAddress) == 1)
                    {
                        DGV_OfficeList[4, DGV_OfficeList.CurrentCell.RowIndex].Value = "Connected";
                        //file.copy(sorucefilenamepath, destinationfilenamepath, true); //copy files...
                    }
                    else if (CheckOffice(OfficeIPAddress) == 0)
                    {
                        DGV_OfficeList[4, DGV_OfficeList.CurrentCell.RowIndex].Value = "disconnected";
                    }
                }
            }
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
        }
    }

ping方法

    public int CheckOffice(string _ipAddress)
    {
        int timeout = 120;
        string data = "PingTestData";
        byte[] buffer = Encoding.ASCII.GetBytes(data);

        Ping PingSender = new Ping();
        PingOptions options = new PingOptions();

        options.DontFragment = true;

        PingReply reply = PingSender.Send(_ipAddress, timeout, buffer, options);

        if (reply.Status == IPStatus.Success)
        {
            return 1;
        }
        else
        {
            return 0;
        }
    }

Answer 1

目前您正在调用CheckOffice三次，一次在新线程中，两次在GUI线程中。不使用新线程中计算的返回值。

尝试更换：

                Thread foregroundthread = new Thread(() => CheckOffice(OfficeIPAddress));
                foregroundthread.Start();

                //check if connection to remote server is available
                if (CheckOffice(OfficeIPAddress) == 1)
                {
                    DGV_OfficeList[4, DGV_OfficeList.CurrentCell.RowIndex].Value = "Connected";
                    //file.copy(sorucefilenamepath, destinationfilenamepath, true); //copy files...
                }
                else if (CheckOffice(OfficeIPAddress) == 0)
                {
                    DGV_OfficeList[4, DGV_OfficeList.CurrentCell.RowIndex].Value = "disconnected";
                }

与

        var task = Task.Run(() =>
            {
                var result = CheckOffice(OfficeIPAddress);

                this.BeginInvoke((Action)(() =>
                {
                    if (result == 1)
                    {
                        DGV_OfficeList[4, DGV_OfficeList.CurrentCell.RowIndex].Value = "Connected";
                        //file.copy(sorucefilenamepath, destinationfilenamepath, true); //copy files...
                    }
                    else if (result == 0)
                    {
                        DGV_OfficeList[4, DGV_OfficeList.CurrentCell.RowIndex].Value = "disconnected";
                    }
                }));
            }
        );

这使用Task而不是显式Thread，如果你只是想启动异步逻辑，然后使用BeginInvoke使用GUI线程将更新应用到GUI，这是更好的做法，否则这将导致DataGridView出现问题控制不是线程安全的。应该在Winforms窗口或Control上定义BeginInvoke，或者您可以查看Dispatcher。

从后台线程更新datagridview

1 个答案: