Question

我对C＃很新，并尝试创建一个辅助方法，该方法根据满足某些条件返回一个对象。它应该能够使用从数据库中提取的正确结果字符串返回自身的对象，但正如您所看到的，我在Var结果声明中收到错误，我也尝试了新的＆＃39;宣言方式，但这也失败了。我用google搜索c＃方法并调用它们，但是教程看起来更基本，而且我已经知道了。

private EmailTemplateContents(User user, int companyId, string template, int cultureId)
        {
            var result = new EmailTemplateContents();
            EmailTemplateContents et = new EmailTemplateContents();
            var extendedInfo = _accountService.GetUserExtendedInfoOrDefault(user.Id, companyId);
            var theCulture = _languageService.GetLanguageCodeOrDefault(extendedInfo.LanguageCode).Culture;
            string theClass = "campaign";

            var bodyTextKey = string.Format("{0}-{1}-bodytext", companyId, template);
            result.BodyText = _resourceProviderService.LocalizationResourceValue(theClass, bodyTextKey, theCulture);

            var subjectKey = string.Format("{0}-{1}-subject", companyId, template);
            result.Subject = _resourceProviderService.LocalizationResourceValue(theClass, subjectKey, theCulture);

            var signatureKey = string.Format("{0}-{1}-signature", companyId, template);
            result.Signature = _resourceProviderService.LocalizationResourceValue(theClass, signatureKey, theCulture);

            var buttonLinkKey = string.Format("{0}-{1}-buttontext", companyId, template);
            result.ButtonText = _resourceProviderService.LocalizationResourceValue(theClass, buttonLinkKey, theCulture);

            return result;
        }

Answer 1

你还没有定义你的方法的名称或返回类型，看起来你错过了方法名称，你的方法定义应该是：

private EmailTemplateContents GetEmailTemplateContents(User user, int companyId, string template, int cultureId)
{
  .................
  ..................
}

所以你的方法最终会像：

private EmailTemplateContents GetEmailTemplateContents(User user, int companyId, string template, int cultureId)
{
    var result = new EmailTemplateContents();

    var extendedInfo = _accountService.GetUserExtendedInfoOrDefault(user.Id, companyId);
    var theCulture = _languageService.GetLanguageCodeOrDefault(extendedInfo.LanguageCode).Culture;
   string theClass = "campaign";

   var bodyTextKey = string.Format("{0}-{1}-bodytext", companyId, template);
   result.BodyText = _resourceProviderService.LocalizationResourceValue(theClass, bodyTextKey, theCulture);

   var subjectKey = string.Format("{0}-{1}-subject", companyId, template);
   result.Subject = _resourceProviderService.LocalizationResourceValue(theClass, subjectKey, theCulture);

   var signatureKey = string.Format("{0}-{1}-signature", companyId, template);
   result.Signature = _resourceProviderService.LocalizationResourceValue(theClass, signatureKey, theCulture);

   var buttonLinkKey = string.Format("{0}-{1}-buttontext", companyId, template);
   result.ButtonText = _resourceProviderService.LocalizationResourceValue(theClass, buttonLinkKey, theCulture);

   return result;
}

Answer 2

这不是辅助方法。这具有构造函数的结构。方法在签名声明中具有返回值：

public ReturnType MethodName(int parameter);

构造函数将只包含带有参数的类名，如您所示。当你拨打这一行时：

var result = new EmailTemplateContents();

编译器需要一个类型为EmailTemplateContents的无参数构造函数。这意味着您要创建该类型的对象。

如果您的班级名为EmailTemplateContents，则需要重命名此方法并为其指定返回值：

private EmailTemplateContents A_different_Name(User user, int companyId, string template, int cultureId)

并确保在类EmailTemplateContents

中有一个无参数构造函数

Answer 3

您还没有给该方法命名，只有一种类型。看起来应该是这样的：

private EmailTemplateContents GetEmailContents(User user, int companyId, string template, int cultureId)
{
}

C＃本身调用方法的语法

3 个答案: