我想在新行的表列中字符串为 表
abc
def
ghi
jkl
答案 0 :(得分:1)
如果您使用SQL SERVER 2016
,请使用STRING_SPLIT
功能
SELECT *
FROM String_split('abc,def,ghi,jkl', ',')
如果你使用的是SQL SREVER 2016
以下的任何东西,那么这里是最好的分割字符串函数。参考here
CREATE FUNCTION [dbo].[Delimitedsplit8k] (@pString VARCHAR(8000),
@pDelimiter CHAR(1))
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000...
-- enough to cover NVARCHAR(4000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
;
GO
调用函数
SELECT *
FROM dbo.DelimitedSplit8K('abc,def,ghi,jkl', ',')
答案 1 :(得分:0)
您可以使用递归CTE分割字符串。它允许您跟踪字符串中字符串的位置(如果需要),并提供返回主表中ID / Key值的链接。 (这使您可以避免使用功能,如果它不是一个选项)
data work.calendrier;
set projet.calendrier;
*do i=1 to 3;
if date= "&vv1"D then savinglight = 1;
*end;
run;