所以有这个stackoverflow问题:
Switch between two frames in tkinter
这看起来像构建应用程序的美丽基础。但是如果在startPage上我希望有多个按钮,并在PageOne上显示相应的数据呢?这是我的尝试:
import tkinter as tk
from functools import partial
characters = {"character1": "abc", "character2": "def", "character3": "ghi", "character4": "jkl", "character5": "mnp", "character6": "qrs" }
class AdventureGame:
''' controller for managiging frames '''
def __init__(self, master):
self.master = master
self.frames = {}
for F in (StartGame,ShowCharacters,CharacterDetail):
frame = F(parent=master, controller=self)
self.frames[F.__name__] = frame
frame.grid(row=0, column=0, sticky="nsew")
''' rais the first frame '''
self.raise_frame("StartGame")
def raise_frame(self,page_name):
''' raise a frame '''
frame = self.frames[page_name]
frame.tkraise()
def lower_frame(self,page_name):
''' lower a frame '''
frame = self.frames[page_name]
frame.lower()
class StartGame(tk.Frame):
''' introduction screen of the game '''
def __init__(self, parent, controller):
super(StartGame,self).__init__(parent)
self.controller = controller
''' introduction text '''
tk.Label(self, text="welcome to this game").grid()
tk.Button(self, text="next", command=lambda: controller.raise_frame("ShowCharacters")).grid()
class ShowCharacters(tk.Frame):
''' main frame, overview of all pokemon '''
def __init__(self, parent, controller):
super(ShowCharacters,self).__init__(parent)
self.controller = controller
for row, character in enumerate(characters):
name_label = tk.Label(self, text=characters[character])
name_label.grid(row=row,column=0)
info_button = tk.Button(self, text="view info", command=partial(self.switch,character))
info_button.grid(row=row,column=1)
def switch(self, character):
test = self.controller.raise_frame("CharacterDetail")
class CharacterDetail(tk.Frame):
''' detail view of pokemon '''
def __init__(self, parent, controller):
super(CharacterDetail,self).__init__(parent)
self.controller = controller
tk.Button(self, text="back", command=lambda: controller.lower_frame("CharacterDetail")).grid()
# somehow display characters name here
def showdetail(self):
tk.Label(self, text="test").grid()
def main():
root = tk.Tk()
app = AdventureGame(root)
root.mainloop()
main()
感觉关键在控制器中,如下所述:
How to get variable data from a class
感觉就像我错过了什么,有人有想法吗?或者我在一起思考错误的方向?
如果我试图显示细节:
def switch(self, character):
test = self.controller.raise_frame("CharacterDetail")
CharacterDetail.showdetail(self)
它显示在ShowCharacters框架而不是CharacterDetail框架
我猜因为self
是框架,它是来自ShowCharacters的self
我需要对控制器做些什么,但我的想法只是空白
所以现在我将信息传递给控制器:
import tkinter as tk
from functools import partial
characters = {"character1": "abc", "character2": "def", "character3": "ghi", "character4": "jkl", "character5": "mnp", "character6": "qrs" }
class AdventureGame:
''' controller for managiging frames '''
def __init__(self, master):
self.master = master
self.frames = {}
for F in (StartGame,ShowCharacters,CharacterDetail):
frame = F(parent=master, controller=self)
self.frames[F.__name__] = frame
frame.grid(row=0, column=0, sticky="nsew")
self.app_data = {"test": "test"}
''' rais the first frame '''
self.raise_frame("StartGame")
def raise_frame(self,page_name):
''' raise a frame '''
frame = self.frames[page_name]
frame.tkraise()
def lower_frame(self,page_name):
''' lower a frame '''
frame = self.frames[page_name]
frame.lower()
class StartGame(tk.Frame):
''' introduction screen of the game '''
def __init__(self, parent, controller):
super(StartGame,self).__init__(parent)
self.controller = controller
''' introduction text '''
tk.Label(self, text="welcome to this game").grid()
tk.Button(self, text="next", command=lambda: controller.raise_frame("ShowCharacters")).grid()
class ShowCharacters(tk.Frame):
''' main frame, overview of all pokemon '''
def __init__(self, parent, controller):
super(ShowCharacters,self).__init__(parent)
self.controller = controller
for row, character in enumerate(characters):
name_label = tk.Label(self, text=characters[character])
name_label.grid(row=row,column=0)
info_button = tk.Button(self, text="view info", command=partial(self.switch,character))
info_button.grid(row=row,column=1)
def switch(self, character):
test = self.controller.raise_frame("CharacterDetail")
CharacterDetail.example(self)
class CharacterDetail(tk.Frame):
''' detail view of pokemon '''
def __init__(self, parent, controller):
super(CharacterDetail,self).__init__(parent)
self.controller = controller
tk.Button(self, text="back", command=lambda: controller.lower_frame("CharacterDetail")).grid()
def example(self):
tk.Label(self, text=self.controller.app_data["test"]).grid()
def main():
root = tk.Tk()
app = AdventureGame(root)
root.mainloop()
main()
标签仍然在错误的框架上,我如何才能访问正确的自我,以便我可以将标签添加到正确的框架中?
答案 0 :(得分:1)
当您在课程CharacterDetail.example(self)
的功能switch(...)
中致电ShowCharacters
时,self
将成为课程ShowCharacters
。因此,在example(self)
类的函数CharacterDetail
中创建的标签将位于ShowCharacters
框架中。
尝试:
返回类raise_frame(...)
的函数AdventureGame
中的凸起框架:
def raise_frame(self, page_name):
frame = self.frames[page_name]
frame.tkraise()
return frame # return the raised frame
修改类switch(...)
的函数ShowCharacters
:
def switch(self, character):
frame = self.controller.raise_frame("CharacterDetail")
frame.example()