Question

我想make sql查询，它将搜索数据库以找到多个最接近的值我有以下查询来查找最接近的值。

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1)
order by abs(price - 50) LIMIT 1;

它的工作正常，但我想让它搜索多个值，如：

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1) //here i want one result (limit 1)
or price >= (50 * 1.9) and price <= (50 * 2.1) //here i want one result (limit 1)
order by abs(price - 50)

我希望每个价格限制1找不到所有值。我怎么能这样做？

//编辑刚刚找到答案。

(select *
  from table
  WHERE price >= (50 * .9) and price <= (50 * 1.1)
  order by abs(price - 50)
  limit 1
) union all
(select *
  from table
  WHERE price >= (50 * 1.9) and price <= (50 * 2.1)
  order by abs(price - 50)
  limit 1
)

Answer 1

你想要这个

吗？

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1) //here i want one result    (limit 1)
 union
SELECT * FROM table
WHERE price >= (50 * 1.9) and price <= (50 * 2.1) //here i want one result  (limit 1)
 order by abs(price - 50)

Answer 2

如何使用union all？

(SELECT *
 FROM table
 WHERE price >= (50 * 0.9) and price <= (50 * 1.1)
 ORDER BY ABS(price - 50)
 LIMIT 1
) UNION ALL
(SELECT *
 FROM table
 WHERE price >= (50 * 1.9) and price <= (50 * 2.1)
 ORDER BY ABS(price - 2*50)
 LIMIT 1
) ;

SQL - 获取多个最接近的值

2 个答案: