Question

这可能是我想念的愚蠢但是：
我得到了这个例外：

Traceback (most recent call last):
  File "P:\Programming\Python\Windows\Console\ProjectHashDec\ProjectHashDec\ProjectHashDec.py", line 29, in <module>
    print(str(j) + ": " + str(int(hex(convertNumbers[j]), times)))
TypeError: 'str' object cannot be interpreted as an integer

我不知道为什么这段代码不起作用：

print("How many hexadecimal numbers do you want to input?")
print("A: 8")
print("B: 16")
print("C: 32")
print("D: 64")

choice = input("What do you choose? > ")
times = 0

if (choice == "A"):
    times = 8
elif (choice == "B"):
    times = 16
elif (choice == "C"):
    times = 32
elif (choice == "D"):
    times = 64`

convertNumbers = []
i = 0
j = 0

while i < times:
    i += 1
    convertNumbers.append(input(str(i) + ": "))

while j < times:
    j += 1
    print(str(j) + ": " + str(int(hex(convertNumbers[j]), times)))

Answer 1

为了让你的代码能够运行，你需要在时间= 64时删除反引号（会给你语法错误），删除“int”（int将不适用于十六进制数字），并更改对convertnumbers的索引调用（第一个索引是0而不是1）。

我不会更改代码中的任何其他内容，但您可以采取一些简单的方法来改进代码。例如，如果userinput不是a，b，c或d，则可以考虑添加一个逻辑，指定所有输入应该是字符串，减少while循环和所需的userinputs数量。

print("How many hexadecimal numbers do you want to input?")
print("A: 8")
print("B: 16")
print("C: 32")
print("D: 64")

choice = input("What do you choose? > ")
times = 0

if (choice == "A"):
   times = 8
elif (choice == "B"):
   times = 16
elif (choice == "C"):
   times = 32
elif (choice == "D"):
   times = 64

convertNumbers = []
i = 0
j = 0

while i < times:
    i += 1
    convertNumbers.append(input(str(i) + ": "))

while j < times:
    j += 1
    print(str(j) + ": " + str((hex(convertNumbers[j-1]), times)))

是什么导致这个“不能被解释为整数”错误？

1 个答案: