Question

我有一个包含4行但列数很多的.xls文件。我将它保存在制表符分隔的.txt文件中，如下所示第一列很重要，每个字符串由,分隔。示例数据可在此处找到https://gist.github.com/anonymous/92a95026f9869790f209dc9ce8f55a59

A,B                   A13   This is India
AFD,DNGS,SGDH         3TR   This is how it is
NHYG,QHD,lkd,uyete    TRD   Where to go
AFD,TTT               YTR   What to do

我希望每行合并一对，如果我们有多个对组合，则保持其他行重复

这就是我要找的东西

A       B        A13    This is India
AFD    DNGS      3TR    This is how it is
AFD    SGDH      3TR    This is how it is
DNGS   SGDH      3TR    This is how it is
NHYG    QHD      TRD    Where to go
NHYG    lkd      TRD    Where to go
NHYG    uyete    TRD    Where to go
QHD     lkd      TRD    Where to go
QHD     uyete    TRD    Where to go
lkd     uyete    TRD    Where to go
AFD     TTT      YTR    What to do

让我们调用我的第一个数据Data

我试过的是逐行阅读

import itertools


lines = open("data.txt").readlines()
for line in lines:
    myrows = line.split(",") 
out_list = []
for i in range(1, len(myrows)+1):
    out_list.extend(itertools.combinations(lines, i))

Answer 1

我认为你有正确的想法使用itertools.combinations()，但你只需要在第一列元素中运行它，而不是在整行上运行它。

这是我的解决方案：

import StringIO
import itertools

data = """"A,B     "    A13 This is India
"AFD,DNGS,SGDH   "  3TR This is how it is
"NHYG,QHD,lkd,uyete"    TRD Where to go
"AFD,TTT"   YTR What to do"""

for line in StringIO.StringIO(data):
    e1,e2 = line.split('\t', 1)  # extract the first part (e1) and the rest of the line (e2)
    es = e1.replace('"','').strip().split(',')  # remove extra "" and whitespace.
                                                # then split each element in a tuple
    for i in itertools.combinations(es,2):  # iterate over all combinations of 2 elements
        print '{}\t{}'.format('\t'.join(i),e2)

结果：

A   B   A13 This is India

AFD DNGS    3TR This is how it is

AFD SGDH    3TR This is how it is

DNGS    SGDH    3TR This is how it is

NHYG    QHD TRD Where to go

NHYG    lkd TRD Where to go

NHYG    uyete   TRD Where to go

QHD lkd TRD Where to go

QHD uyete   TRD Where to go

lkd uyete   TRD Where to go

AFD TTT YTR What to do

修改

这是修改后的版本。请注意enumerate() f.readlines()返回当前行的索引

import itertools with open('data.txt') as f: header = f.readline() with open('result.txt','w') as w: w.write(header) for n,line in enumerate(f.readlines()): elems = line.split('\t') e0 = elems[0].split(',') e0 = [e.replace('"','').strip() for e in e0] for pairs in itertools.combinations(e0,2): w.write('{:d}\t{}\t{}\n'.format(n+1,'\t'.join(pairs),'\t'.join(elems[1:])))

Answer 2

you_data.txt：

"Q92828, O60907, O75376"    15  NCOR complex        Human   MI:0004- affinity chromatography technologies | MI:0019- coimmunoprecipitation | MI:0069- mass spectrometry studies of complexes    12628926    "By using specific small interference RNAs (siRNAs), the authors demonstrate that HDAC3 is essential, whereas TBL1 and TBLR1 are functionally redundant but essential for repression by unliganded thyroid hormone receptor."
"O15143, O15144, O15145, P61158, P61160, P59998, O15511"    27  Arp2/3 protein complex      Human   MI:0027- cosedimentation | MI:0071- molecular sieving   9359840
"Q9UL46, Q06323"    30  PA28 complex     11S REG    Human   MI:0071- molecular sieving | MI:0226- ion exchange chromatography   9325261 "PA28 is a regulatory complex of the 20S proteasome. It acts as proteasome activator and stimulates cleavage after basic, acidic, and most hydrophobic residues in many peptides."
"P55036, P62333, O43242, P35998, P48556, P62191, Q13200, Q99460, O00232, P17980, P62195, O00487, P51665, Q15008, O75832, O00233"    32  PA700 complex    19S complex    Human   MI:0226- ion exchange chromatography | MI:0071- molecular sieving   9148964 "The proteasome is an essential component of the ATP-dependent proteolytic pathway in eukaryotic cells and is responsible for the degradation of most cellular proteins (for reviews see PMID:8811196 and PMID:10872471). It contains a barrel-shaped proteolytic core complex (the 20S proteasome), and is capped at one or both ends by regulatory complexes like the 19S complex (PMID:11812135), modulator (PMID:8621709), PA28 (PMID:9325261) and PA28gamma (PMID:9325261). Interferon-gamma (IFN-gamma) alters the peptide-degrading specificity of proteasomes and produces an immunoproteasome responsible for accelerated processing of nonself endogenous antigens by inducing the replacement of subunits Psmb5, Psmb6 and Psmb7 by Psmb8, Psmb9 and Psmb10, respectively."

代码：

import itertools

with open('you_data.txt') as f:
    index = 1
    for line in f:
        split_line = line.split('"')
        key = split_line[1].strip().split(',', 2)
        value = split_line[2].strip().replace('\t',' ')

        for pair in itertools.combinations(key, 2):
            pair = [i.strip() for i in pair]
            print('{:<4}{:8}{:8}{:20}'.format(index,*pair, value))
        index += 1

出：

1   Q92828  O60907  15 NCOR complex  Human MI:0004- affinity chromatography technologies | MI:0019- coimmunoprecipitation | MI:0069- mass spectrometry studies of complexes 12628926
1   Q92828  O75376  15 NCOR complex  Human MI:0004- affinity chromatography technologies | MI:0019- coimmunoprecipitation | MI:0069- mass spectrometry studies of complexes 12628926
1   O60907  O75376  15 NCOR complex  Human MI:0004- affinity chromatography technologies | MI:0019- coimmunoprecipitation | MI:0069- mass spectrometry studies of complexes 12628926
2   O15143  O15144  27 Arp2/3 protein complex  Human MI:0027- cosedimentation | MI:0071- molecular sieving 9359840
2   O15143  O15145, P61158, P61160, P59998, O1551127 Arp2/3 protein complex  Human MI:0027- cosedimentation | MI:0071- molecular sieving 9359840
2   O15144  O15145, P61158, P61160, P59998, O1551127 Arp2/3 protein complex  Human MI:0027- cosedimentation | MI:0071- molecular sieving 9359840
3   Q9UL46  Q06323  30 PA28 complex  11S REG Human MI:0071- molecular sieving | MI:0226- ion exchange chromatography 9325261
4   P55036  P62333  32 PA700 complex  19S complex Human MI:0226- ion exchange chromatography | MI:0071- molecular sieving 9148964
4   P55036  O43242, P35998, P48556, P62191, Q13200, Q99460, O00232, P17980, P62195, O00487, P51665, Q15008, O75832, O0023332 PA700 complex  19S complex Human MI:0226- ion exchange chromatography | MI:0071- molecular sieving 9148964
4   P62333  O43242, P35998, P48556, P62191, Q13200, Q99460, O00232, P17980, P62195, O00487, P51665, Q15008, O75832, O0023332 PA700 complex  19S complex Human MI:0226- ion exchange chromatography | MI:0071- molecular sieving 9148964

Answer 3

这让我想起了flatmap。

import itertools def tolist(s): return s.split(',') def tostring(l): return [','.join([l[i],l[j]]) for i in range(len(l)) for j in range(len(l)) if i <j] def tomult(ll): return map( lambda x: [x]+ll[1:] ,tostring(tolist(ll[0]))) def tofmap(lines): return list(itertools.chain(*map( lambda line: tomult(line) ,lines))) a = [['c1,c2', '200', 'line one'], ['a,b,c', '100', 'this is good']] b = tofmap(a)

如何为每条线组成一对

3 个答案: