String.Index没有名为advancedBy - swift的成员

Question

我需要验证医疗保险号码，并且我跟随此主题：How do I validate an Australian Medicare number?

我收到错误

代码是：String.Index does not have a member named advancedBy

 let matches = expression.matchesInString(medicareNumber, options: NSMatchingOptions.ReportProgress, range: NSMakeRange(0, length))


        if (matches.count > 0 && matches[0].numberOfRanges > 2) {
            let base = medicareNumber.substringWithRange(medicareNumber.startIndex...medicareNumber.startIndex.advancedBy(matches[0].rangeAtIndex(1).length))
            let checkDigitStartIndex = medicareNumber.startIndex.advancedBy(matches[0].rangeAtIndex(2).location )
            let checkDigitEndIndex = checkDigitStartIndex.advancedBy(matches[0].rangeAtIndex(2).length)
            let checkDigit = medicareNumber.substringWithRange(checkDigitStartIndex..<checkDigitEndIndex)
            var total = 0

            for i in 0..<multipliers.count {
                total += Int(base.charAtIndex(i))! * multipliers[i]
            }

            return (total % 10) == Int(checkDigit)
        }

我正在使用Xcode 6.2，我该如何解决这个问题？请注意我需要在没有升级Xcode的情况下解决这个问题。

Answer 1

Swift 1.2

使用<span *ngIf="orderBy=='asc'" [ngStyle]="{'height': value+ '%'}"></span> <span *ngIf="orderBy=='desc'" [ngStyle]="{'height': value+ '%'}"></span>

advance

Swift 2

Swift2中已弃用

let base = medicareNumber.substringWithRange( medicareNumber.startIndex...advance( medicareNumber.startIndex, matches[0].rangeAtIndex(1).length ) ) 使用advance

advanceBy

Swift 3

在Swift3中已弃用

let base = medicareNumber.substringWithRange( medicareNumber.startIndex...medicareNumber.startIndex.advancedBy( matches[0].rangeAtIndex(1).length ) ) 使用advancedBy(_:)

index(_:offsetBy:)