Question

我是BASH脚本中的新手。我有一个csv文件，其中2列用逗号分隔。

ASDP01,01989015064
KSDP03,01988683270
KSDP06,01945993069
CSDP11,01990721863
CSDP13,01955883155
ASDP12,01953889744
CSDP11,01956798684
ASDP11,01959969994
KSDP01,01924824056

我想从另一个文本文件中添加另外两列。这是写在文本文件中的：

662,2016-12-31

从tex文件添加后，csv文件将如下所示

ASDP01,01989015064,662,2016-12-31
KSDP03,01988683270,662,2016-12-31
KSDP06,01945993069,662,2016-12-31
CSDP11,01990721863,662,2016-12-31
CSDP13,01955883155,662,2016-12-31
ASDP12,01953889744,662,2016-12-31
CSDP11,01956798684,662,2016-12-31
ASDP11,01959969994,662,2016-12-31
KSDP01,01924824056,662,2016-12-31

任何人都可以帮我这个吗？

Answer 1

我认为file2.csv只包含一行662,2016-12-31。

string="$(cat file2.csv)"
sed 's/.*/&,'"$string"'/' file1.csv > new.csv

输出到new.csv：

ASDP01,01989015064,662,2016-12-31
KSDP03,01988683270,662,2016-12-31
KSDP06,01945993069,662,2016-12-31
CSDP11,01990721863,662,2016-12-31
CSDP13,01955883155,662,2016-12-31
ASDP12,01953889744,662,2016-12-31
CSDP11,01956798684,662,2016-12-31
ASDP11,01959969994,662,2016-12-31
KSDP01,01924824056,662,2016-12-31

请参阅：The Stack Overflow Regular Expressions FAQ

Answer 2

您也可以使用awk来完成结果。

#cat file1
KSDP01,01989015064
KSDP03,01988683270
KSDP06,01945993069
CSDP11,01990721863
CSDP13,01955883155
ASDP12,01953889744
CSDP11,01956798684
ASDP11,01959969994
KSDP01,01924824056

#cat file2
662,2016-12-31

#awk -v f2content="$(<file2)" '{$0=($0 "," f2content)}1' file1
KSDP01,01989015064,662,2016-12-31
KSDP03,01988683270,662,2016-12-31
KSDP06,01945993069,662,2016-12-31
CSDP11,01990721863,662,2016-12-31
CSDP13,01955883155,662,2016-12-31
ASDP12,01953889744,662,2016-12-31
CSDP11,01956798684,662,2016-12-31
ASDP11,01959969994,662,2016-12-31
KSDP01,01924824056,662,2016-12-31

请参阅[ awk concatenation ]。

Answer 3

另一个sed替代

$ sed 's/$/,'"$(cat file2)"'/' file1

从另一个文件添加列

3 个答案: