有时只能从mysql转换为mysqli

Question

我有从Mysql到mysqli（程序）的转换问题。 在使用mysqli设置后，两段看起来基本相同的代码工作方式不同。

有第一个。工作

<?php 
$dotaz =    'SELECT *
            FROM portfolio
            WHERE stav = "normal" 
            ORDER BY poradi ASC';
$vysledky = mysqli_query($link, $dotaz);
while($radek = mysqli_fetch_array($vysledky)) {
    extract($radek);
        $dotaz2 =   'SELECT url, alt_cs
                     FROM img
                     WHERE category="items" and id_item="'.$id.'" and thumb=1 
                     ORDER BY id DESC';
        $vysledky2 = mysqli_query($link,$dotaz2);
        while($radek2 = mysqli_fetch_array($vysledky2)) {
        extract($radek2);}
    echo '
        <a href="cs/portfolio/'.$id.'">
        <div class="select">
            <img src="'.$url.'" class="select-img" alt="'.$alt_cs.'">
            <div class="select-popis">
                <h2>'.$name_cs.'</h2>
                <p class="mini">'.$category_cs.'</p>
           </div>
           </div>
    </a>
        ';
    }   
?>

还有第二个，不工作。

警告：mysqli_query（）期望参数1为mysqli，字符串在第62行的D：\ 00 FLEKAL.COM \ cs \ download-list.php中给出

<?php 
$dotaz =    'SELECT *
            FROM download 
            ORDER BY id DESC';
$vysledky = mysqli_query($link, $dotaz);
while($radek = mysqli_fetch_array($vysledky)) {
    extract($radek);
        $dotaz2 =   'SELECT url, alt_cs
                     FROM img
                     WHERE category="down" and id_item="'.$id.'" and thumb = 1 
                     ORDER BY id DESC';
        $vysledky2 = mysqli_query($link,$dotaz2);
        while($radek2 = mysqli_fetch_array($vysledky2)) {
        extract($radek2);}
    echo '
        <a href="cs/download/'.$id.'">
        <div class="select-img-down" style="background-image: url('.$url.')"></div>
    </a>
        ';
    }   
?>

谢谢。