我试图用RxSwift重现一个简单的计时器。
我只有暂停/播放按钮,可用于暂停和恢复。
gameTimer = Observable<NSInteger>.interval(1, scheduler: MainScheduler.instance)
.subscribeNext({ sec -> Void in
print("\(sec) s")
}).addDisposableTo(disposeBag!)
pauseResumeButton.rx_tap
.map{ !self.isRunning.value }
.startWith(true)
.bindTo( isRunning )
.addDisposableTo(disposeBag!)
isRunning显然是一个变量。 我可以停止计时器设置disposeBag = nil但是我不能暂停它.... itried过滤事件但计数显然继续增长...
任何人都可以帮助我吗?谢谢!
答案 0 :(得分:17)
一个小技巧:
class ViewController: UIViewController {
let isRunning = Variable(true)
override func viewDidLoad() {
super.viewDidLoad()
isRunning.asObservable()
.debug("isRunning")
.flatMapLatest { isRunning in
isRunning ? Observable<Int>.interval(1, scheduler: MainScheduler.instance) : .empty()
}
.flatMapWithIndex { (int, index) in Observable.just(index) }
.debug("timer")
.subscribe()
.addDisposableTo(disposeBag)
navigationItem.rightBarButtonItem!.rx.tap
.subscribe(onNext: { [unowned self] in
self.isRunning.value = !self.isRunning.value
})
.addDisposableTo(disposeBag)
}
}
结果:
2016-12-17 20:53:11.408: timer -> subscribed
2016-12-17 20:53:11.414: isRunning -> subscribed
2016-12-17 20:53:11.415: isRunning -> Event next(true)
2016-12-17 20:53:12.503: timer -> Event next(0)
2016-12-17 20:53:13.488: timer -> Event next(1)
2016-12-17 20:53:14.488: timer -> Event next(2)
2016-12-17 20:53:15.488: timer -> Event next(3)
2016-12-17 20:53:16.154: isRunning -> Event next(false)
2016-12-17 20:53:23.155: isRunning -> Event next(true)
2016-12-17 20:53:24.223: timer -> Event next(4)
2016-12-17 20:53:25.229: timer -> Event next(5)
2016-12-17 20:53:26.228: timer -> Event next(6)
2016-12-17 20:53:27.220: timer -> Event next(7)
2016-12-17 20:53:28.225: timer -> Event next(8)
2016-12-17 20:53:29.221: timer -> Event next(9)
2016-12-17 20:53:29.971: isRunning -> Event next(false)