Question

我试图从getParams（）调用一个方法，但没有任何反应，是从getParams（）调用还是错误的正确方法？这个方法getDrugId(drugNames.get(i));返回一个值，但当我把它放在getparams（）;没有任何反应。

{
                @Override
                protected Map<String, String> getParams() throws AuthFailureError {

                    Map<String, String> params = new HashMap<String, String>();
                    for (int i = 0; i<drugNames.size(); i++){

                        params.put("drid["+i+"]",getDrugId(drugNames.get(i)));
                        params.put("paid", 1+"");
                    }



                    return params;
                }

private String getDrugId(final String drugName) {



        StringRequest stringRequest = new StringRequest(Request.Method.POST, Config.ROOT + Config.GETRUGSIDS, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {


                    drID=response.trim();
//                    Toast.makeText(getApplicationContext(), response, Toast.LENGTH_LONG).show();

            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {

                if (error instanceof TimeoutError) {
                    Toast.makeText(getApplicationContext(), "time out Error", Toast.LENGTH_LONG).show();
                } else if (error instanceof NoConnectionError) {
                    Toast.makeText(getApplicationContext(), "no Connection Error", Toast.LENGTH_LONG).show();
                } else if (error instanceof AuthFailureError) {
                    Toast.makeText(getApplicationContext(), "Authenticatin Failure Error", Toast.LENGTH_LONG).show();
                } else if (error instanceof NetworkError) {
                    Toast.makeText(getApplicationContext(), "Network Error", Toast.LENGTH_LONG).show();
                } else if (error instanceof ServerError) {
                    Toast.makeText(getApplicationContext(), "Server Error", Toast.LENGTH_LONG).show();
                } else if (error instanceof ParseError) {
                    Toast.makeText(getApplicationContext(), "JASON Parse Error", Toast.LENGTH_LONG).show();
                }

            }
        }) {
            @Override
            protected Map<String, String> getParams() throws AuthFailureError {
                Map<String, String> params = new HashMap<String, String>();

                params.put("drNAM",drugName);

                return params;
            }
        };

        MySingleton.getInstance(getApplicationContext()).addToRequestQueue(stringRequest);
        return drID;
    }

Answer 1

您正在调用方法getDrugId(drugNames.get(i));而不对结果做任何事情。

您可能应该将结果用作索引，就像这样，对吗？

            @Override
            protected Map<String, String> getParams() throws AuthFailureError {

                Map<String, String> params = new HashMap<String, String>();
                for (int i = 0; i<drugNames.size(); i++){

                    params.put("drid["+getDrugId(drugNames.get(i))+"]",drugNames.get(i));
                    params.put("paid", 1+"");
                }



                return params;
            }

Answer 2

getDrugId(drugNames.get(i));这应该会返回一些价值，对吗？但是你无法分配方法调用在代码中返回的值。此外，如果您考虑使用此方法调用返回的内容，您是否可以调试并检查getDrugId(xxx)返回的内容。

从getParams（）调用方法

2 个答案: