OkHttpClient client = getOkHttpClient();
Request request = new Request.Builder()
.url("https://nghttp2.org:443") // The Http2Server should be running here.
.build();
try {
Socket socket = client.socketFactory().createSocket();
Http2Connection con = new Http2Connection.Builder(true)
.socket(socket)
.pushObserver(new PushObserver(){
@Override
public boolean onRequest(int streamId, List<Header> requestHeaders) {
// do something here
return true;
}
@Override
public boolean onHeaders(int streamId,
List<Header> responseHeaders, boolean last) {
// do something here
return true;
}
@Override
public boolean onData(int streamId, BufferedSource source,
int byteCount, boolean last) throws IOException {
// do something here
return true;
}
@Override
public void onReset(int streamId, ErrorCode errorCode) {
// do something
}
}).build();
} catch (IOException e) {
LOG.error("IOException", e);
}
我想将行value_deal转换为具有相同月份的列,并将其作为视图,就像这样。
+-----+----------+
|month|value_deal|
+-----+----------+
|JAN |10 |
+-----+----------+
|JAN |20 |
+-----+----------+
|FEB |30 |
+-----+----------+
|FEB |40 |
+-----+----------+
我尝试过使用动态转换行到here中的列。但是我无法在Create View函数中插入代码。
有人可以帮忙吗? PLS
答案 0 :(得分:0)
我将表测试命名为以下查询返回所需的结果
SELECT QRY.M,
SUBSTRING_INDEX(SUBSTRING_INDEX(QRY.CONC, ',', 1), ',', -1) as value_deal1,
SUBSTRING_INDEX(SUBSTRING_INDEX(QRY.CONC, ',', 2), ',', -1) as value_deal2
FROM (SELECT MONTH AS M, GROUP_CONCAT(value_deal) AS CONC
FROM test1
GROUP BY MONTH) QRY;
基本上使用group concat函数在一列中获取month的所有值,然后使用in built string函数将列拆分为多个列。
这是demo