我通过传递过滤器从db获得结果。目前我已通过code
列表,我收到了正确的数据。以下是代码。
public DataTable getData(IList<string> Code,
IList<string> category,
IList<string> state,
IList<string> Type,
IList<string> general)
{
DataTable dt = new DataTable();
var result = _db.Sample.Where(x => Code.Contains(x.Code));
if (result == null)
{
return null;
}
else
{
dt = Utility.ToDataTable(result.ToList());
}
return dt;
}
我必须传递4个过滤器,即category, state, type and general
。此外,我必须检查它们是否都为空。
我不确定如何检查null的值,然后将其传递给查询。
任何建议都将不胜感激
答案 0 :(得分:1)
您可以检查是否所有5都为空,然后执行lambda
表达式。要为4个额外过滤器添加条件,请使用&&
运算符并将其与代码过滤器一起添加。
public DataTable getData(IList<string> Code, IList<string> category, IList<string> state, IList<string> Type, IList<string> general)
{
DataTable dt = new DataTable();
if(code==null)
code=''
if(category==null)
category=''
if(state==null)
state=''
if(general==null)
general=''
var result = _db.Sample.Where(x => (Code.Contains(x.Code) || Code=='') && (category.Contains(x.category)|| category=='') && (state.Contains(x.state)||state=='') && (general.Contains(x.general)||general==''))
if (result == null)
{
return null;
}
else
{
dt = Utility.ToDataTable(result.ToList());
}
return dt;
}
答案 1 :(得分:1)
我不确定您是要检查包含所有列表还是只检查其中任何一个列表。我',为两者提供解决方案
public DataTable getData(IList<string> Code, IList<string> category, IList<string> state, IList<string> Type, IList<string> general)
{
DataTable dt = new DataTable();
var result = null;
//result = _db.Sample.Where(x => Code.Contains(x.Code) && category.Contains(x.category) && state.Contains(x.state) && general.Contains(x.general));
//if you wish to check for any one
result = _db.Sample.Where(x => (Code != null && Code.Contains(x.Code)) || (category != null && category.Contains(x.category)) || (state != null && state.Contains(x.state)) || (general != null && general.Contains(x.general)));
if (result == null)
{
return null;
}
else
{
dt = Utility.ToDataTable(result.ToList());
}
return dt;
}