Question

amount_of_names = int(input("Input amount of players: "))
names = []

for counter in range(amount_of_names):
    name = str(input("Input players first name: "))
    names.append(name)
#print (names)
selected_name = str(input("Input your name: "))
import random 
names2 = random.choice(names)
while True:
    if name != names2:
        import random 
        names2 = random.choice(names)
        print (name, names2)
        break
    else: names2 = random.choice(names)

Input amount of players: 6
Input players first name: aa
Input players first name: ss
Input players first name: dd
Input players first name: ff
Input players first name: gg
Input players first name: hh
Input your name: ss
hh hh

我希望＆＃34;而真实＆＃34;声明一直运行到＆＃34; name＆＃34;和＆＃34;名字＆＃34;不匹配，如果名称不匹配，则打印不匹配的名称。 Atm我只收到一封信作为输出或语法错误，同时试图使其正常工作，如果它已经在列表中，实际上无法与他们的名字匹配 - 如果有人可以帮助它将非常感激

ArrangementNode

Answer 1

amount_of_names = int(input("Input amount of players: "))
names = []

for counter in range(amount_of_names):
  name = str(input("Input players first name: "))
  names.append(name)
#print (names)
selected_name = str(input("Input your name: "))
import random 
names2 = random.choice(names)
while True:
    if name != names2:
        print (name,names2)
        break
    else:
        names2 = random.choice(names)

同时为true：检查名称中是否有名称

1 个答案: