Question

我收到上述类型错误：

TypeError：无法隐式地将'int'对象转换为str。

第34行，<lambda>

output[column] = output['Index_for_s'].apply(lambda x: s(x, column, file_two))

尝试运行以下程序时：

import pandas as pd

import os


def get_index(x, data):
    return list(data[data['COL1'] == x].index)


def suvrule(ind, col, data):
    data=pd.DataFrame(data)
    return  data.ix [ind,col].sum() 

file_one_path = input('Please enter file one: ')
file_two_path = input('Please enter file two: ')

if os.path.exists(file_one_path) and os.path.exists(file_two_path):
    file_one = pd.read_csv(file_one_path)
    file_two = pd.read_csv(file_two_path)
    try:
        assert (file_one.shape[0] == file_one.shape[0])
    except AssertionError:
        print ("Check Data.")
        exit()

    output = file_one.groupby('COL1', sort='False')['COL2'].agg('count').reset_index()
    output['Index_for_s'] = output['COL1'].apply(lambda x: get_index(x, file_one))
    cols_for_s = [col for col in file_two.columns if 'Header' not in col]
    for column in cols_for_s:
        output[column] = output['Index_for_s'].apply(lambda x: s(x, column, file_two))
    output = output.drop('Index_for_s', axis= 1)
    print ("\nWriting output to output.csv in current working directory.")
    output.to_csv("output.csv",  index='False')
else:
    print ('Incorrect file path')

Answer 1

试试这个：将行更改为此。 [STR（Index_for_s）]

程序返回以下TypeError：无法隐式地将'int'对象转换为str

1 个答案: