Question

我在Oracle中生成一个脚手架视图，用于我需要的其他工作。我一般都是在Oracle和SQL中沾沾自喜。

我想得到这个：

GridView

由此：

DATE_       I           II          III
13-DEC-16   CATEGORY    SUBCATEGORY SITE_NAME_A
13-DEC-16   CATEGORY    SUBCATEGORY SITE_NAME_B
13-DEC-16   CATEGORY    SUBCATEGORY SITE_NAME_C
14-DEC-16   CATEGORY    SUBCATEGORY SITE_NAME_A
14-DEC-16   CATEGORY    SUBCATEGORY SITE_NAME_B
14-DEC-16   CATEGORY    SUBCATEGORY SITE_NAME_C
...

这当然有效，如果子查询返回单个记录，但会抛出太多记录＆＃34;什么时候没有错误。我怎么能解决这个问题？我想获得额外的记录，因为它们是新的网站名称，但不知道如何在视图中插入它们。

谢谢！

编辑：为了澄清，供应商可能有多个vendor_site，当太多记录错误合并时。还注意到输出示例是错误的，纠正了它。

Answer 1

可能您正在寻找那个(SELECT UNIQUE VENDOR_SITE_CODE FROM AP_INVOICES_V WHERE VENDOR_NAME = 'SOMETHING') AS III

的the docs

Answer 2

如果您需要新的站点名称作为附加行，那么而不是使其成为子查询，将其与主表连接并使用distinct来避免重复记录。根据需要添加或删除WHERE子句

SELECT distinct TRUNC (SYSDATE - (3) + (LEVEL)) AS DATE_,
              'CATEGORY' AS I,
              'SUBCATEGORY' AS II,                  
              VENDOR_SITE_CODE  AS III,
              VENDOR_NAME,
              LEVEL
         FROM DUAL,AP_INVOICES_V WHERE VENDOR_NAME = 'SOMETHING'
        CONNECT BY LEVEL <= (SYSDATE - (SYSDATE - (3)))

如果要在现有行中添加新站点名称，请使用Oracle分析函数LISTAGG和VENDOR_NAME分区

SELECT  TRUNC (SYSDATE - (3) + (LEVEL)) AS DATE_,
          'CATEGORY' AS I,
          'SUBCATEGORY' AS II,                 
         ( SELECT DISTINCT LISTAGG(VENDOR_SITE_CODE,',') WITHIN GROUP (ORDER BY VENDOR_SITE_CODE) OVER (PARTITION BY VENDOR_NAME) FROM AP_INVOICES_V WHERE VENDOR_NAME='VENDOR1') AS III
     FROM DUAL
    CONNECT BY LEVEL <= (SYSDATE - (SYSDATE - (3)))

ORA-01427 - 子查询返回多条记录

2 个答案: