Question

我有以下表格

    <form action="/wp-content/themes/wallstreet/welcome.php" method="post" class="basic-grey">
<h1>Form
<span>Please fill all the texts in the fields.</span>
</h1>
<label>
<span>Your Nickname* :</span>
<input id="name" type="text" name="name" placeholder="It will appear in the text" />
</label>

<label>
<span>Your Email* :</span>
<input id="email" type="email" name="email" placeholder="Valid Email Address" />
</label>

<label>
<span>Message* :</span>
<textarea id="messagebook" name="messagebook" placeholder="The text that will appear" maxlength="80"></textarea>
</label>
<label>
<span>Code* :</span>
<input id="code" type="text" name="code" placeholder="The Code That we sent to your email" maxlength="8" />
</label>
<label>
<span> </span>
<input type="submit" class="button" value="Send" />
</label>
</form>

使用以下php，这个php基本上将消息值发布到txt文件

<?php
$var = $_POST['messagebook'];
file_put_contents("/var/www/wordpress/wp-content/themes/wallstreet/data.txt", $var . "\n", FILE_APPEND);
exit();
?>

但我希望提交按钮仅在我的代码字段与存储在txt文件中的代码匹配时才有效

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理论上我可以使用此代码，但我不知道在哪里实现它

    function is_valid($code)
{
return in_array($code , explode(' ',file_get_contents('coderoute')));
}

EDIT1：好像我有这个，我得到这个错误

 <?php
    function is_valid($code)
    {
    return in_array($code , explode(' ',file_get_contents("/wp-content/themes/wallstreet/codes.txt")));
    } 
    $code = $_POST['code'];
    if (is_valid($code)) { 
        $var = $_POST['messagebook'];
        file_put_contents("/var/www/wordpress/wp-content/themes/wallstreet/data.txt", $var . "\n", FILE_APPEND);
    }
    exit();
?>

PHP警告： file_get_contents（/wp-content/themes/wallstreet/codes.txt）：未能 open stream：没有这样的文件或目录第4行的/var/www/wordpress/wp-content/themes/wallstreet/welcome.php，

Answer 1

您需要检查的代码位于$_POST['code']。

因此将其作为参数传递给is_valid函数：

<?php
    $code = $_POST['code'];
    if (is_valid($code)) { 
        $var = $_POST['messagebook'];
        file_put_contents("/var/www/wordpress/wp-content/themes/wallstreet/data.txt", $var . "\n", FILE_APPEND);
    }
    exit();
?>

Answer 2

[::-1]

您已提及$code = $_POST['code']; $message_book = $_POST['messagebook']; if(is_valid($code)) { file_put_contents('/var/www/wordpress/wp-content/themes/wallstreet/data.txt', "{$message_book}\n", FILE_APPEND); exit(); } function is_valid($code) { $codes = file('/var/www/wordpress/wp-content/themes/wallstreet/codes.txt', FILE_IGNORE_NEW_LINES); return in_array($code, $codes); }的{{1}}。您可以提供PHP Warning的绝对路径来检查它是否正常工作。

Answer 3

您可以使用带有代码的JavaScript数组，此数组将填充PHP ，如果输入的代码不在数组中，则提交按钮将不会提交表单。

将下一个代码复制粘贴到PHP文件中，然后在浏览器中打开它：

<html>
  <head>
    <script type="text/javascript">
function check_code () // ◄■ FUNCTION CALLED FROM THE FORM.
{ var arr = [ <?php // ▼ FILL JAVASCRIPT ARRAY WITH CODES FROM FILE ▼
              $arr = explode( PHP_EOL,file_get_contents('coderoute.txt') );
              echo "'" . implode( "','",$arr ) . "'";
              ?> ];
  var code = document.getElementById("code"); // ◄■ FIELD IN FORM.
  if ( arr.indexOf( code.value ) == -1 ) // ◄■ SEARCH CODE IN ARRAY.
       { alert("Code not found.");
         return false; // ◄■ FORM WILL NOT BE SUBMITTED.
       }
  return true; // ◄■ FORM WILL BE SUBMITTED.
}
    </script>
  </head>
  <body>
    <form action="somescript.php" onsubmit="return check_code()"> <!-- ◄■ JS FUNCTION -->
      <input type="text" id="code" name="code"/> <!-- ◄■ CODE FIELD -->
      <br/>
      <input type="submit" value="Submit"/>
    </form>
  </body>
</html>

注意JavaScript数组是如何用PHP填充的，PHP脚本从文件中读取代码并将它们作为JavaScript数组的数组项进行回显。 右键单击页面以查看源代码并观察JavaScript数组的填充方式。

如何在我的提交表单中实现代码检查

3 个答案: