从How do I run an terminal command in a swift script? (e.g. xcodebuild)复制:
import Foundation
@discardableResult
func shell(_ args: String...) -> Int32 {
let task = Process()
task.launchPath = "/usr/bin/env"
task.arguments = args
task.launch()
task.waitUntilExit()
return task.terminationStatus
}
shell("ls")
shell("xcodebuild", "-workspace", "myApp.xcworkspace")
这看起来很整洁。我只是想知道如何为流程设置$PWD
等环境变量(这里名为task
...)。
我尝试了以下内容:
import Foundation
@discardableResult
func execCommand(_ args: String...) -> Int32 {
let process = Process()
process.launchPath = "/usr/bin/env"
process.environment = ["PWD": "/Users"]
if let env = process.environment {
print(env["PWD"] ?? "Unknown")
} else {
print("Environment not available!")
}
process.arguments = args
process.launch()
process.waitUntilExit()
return process.terminationStatus
}
execCommand("pwd")
打印出这些线条:
/Users
/private/tmp/AppIcon.appiconset
显然已经设置了环境变量,但根本没有对pwd命令产生任何影响。
另一种方法:
import Foundation
@discardableResult
func execCommand(_ args: String...) -> Int32 {
let process = Process()
process.launchPath = "/usr/bin/env"
var environment = ProcessInfo.processInfo.environment
environment["PWD"] = "/Users" //optionally set new vars, or overwrite old ones
process.environment = environment
if let env = process.environment {
print(env["PWD"] ?? "Unknown")
} else {
print("Environment not available!")
}
process.arguments = args
process.launch()
process.waitUntilExit()
return process.terminationStatus
}
execCommand("pwd")
不幸的是,结果和以前一样。
答案 0 :(得分:4)
您只需将Process
的{{3}}变量设置为包含变量的[String: String]
值映射。
let process = Process()
// ...
process.environment = ["home": "/Users/foo"]
如果您想传递当前环境,可以这样做:
let process = Process()
// ...
let environment = ProcessInfo.processInfo.environment
environment["home"] = "/Users/foo" //optionally set new vars, or overwrite old ones
process.environment = environment
如果要设置工作目录,这不是由环境变量决定的,而是通过environment
。
let process = Process()
// ...
process.currentDirectoryPath = "/Users"