继续异常并转到下一个语句python

Question

假设我有一大堆代码，每当我遇到异常时我都会忽略它并继续下一行。这在python中可能吗？我想要像 -

这样的东西

try:
   #some code here
   #see an exception, ignore, continue to next line
   #more code
   #any more code , ignore and march on through rest of block
except:
   pass

Answer 1

是的，你可以这样做，try-except必须围绕每一行，一旦行抛出异常，它将转到异常语句然后转到下一行。你最好打印/记录异常行。

for line in inputs:
    try:
        # your code here
    except Exception as e:
        # log your exception here