从oracle数据库添加行到绑定的datagridview

时间:2016-12-15 15:42:02

标签: c# oracle winforms datagridview

我正在尝试构建由两部分组成的datagridview 一部分来自数据库,另一部分是收集有关本地硬盘上文件的信息并将其显示为一部分,但我收到错误消息

  

无法以编程方式将行添加到datagridview行   控件是数据绑定时的集合

注意: 知道datagridview中的数据将在以后用于修改oracle数据库上的数据

我上传了图片,以便更好地了解前两列来自数据库

private void ListFileToBePatched()
{
    try
    {
        string connstr = "data source=orcl;user id=user;password=pwd";
        string cmdstr = @"SELECT OFFICE_CODE as ""Office Code"",
                                 IP_ADDRESS  as ""Office IP"" 
                            FROM table";

        string[] array = Directory.GetFiles(SBankfilespath, "*.txt");

        using (OracleConnection conn = new OracleConnection(connstr))
        using (OracleCommand cmd = new OracleCommand(cmdstr, conn))
        {
            conn.Open();
            OracleTransaction trans = conn.BeginTransaction();

            OracleDataReader OraReader = cmd.ExecuteReader();

            DataTable dt = new DataTable();

            DataColumn OfficeCodecolumn = new DataColumn();
            OfficeCodecolumn.DataType = System.Type.GetType("System.String");
            OfficeCodecolumn.ColumnName = "Office Code";
            dt.Columns.Add(OfficeCodecolumn);

            DataColumn OfficeIPcolumn = new DataColumn();
            OfficeIPcolumn.DataType = System.Type.GetType("System.String");
            OfficeIPcolumn.ColumnName = "Office IP Address";
            dt.Columns.Add(OfficeIPcolumn);

            DataColumn FileNamecolumn = new DataColumn();
            FileNamecolumn.DataType = System.Type.GetType("System.String");
            FileNamecolumn.ColumnName = "File Name";
            dt.Columns.Add(FileNamecolumn);

            DataColumn FullFilePathcolumn = new DataColumn();
            FullFilePathcolumn.DataType = System.Type.GetType("System.String");
            FullFilePathcolumn.ColumnName = "Full File Path";
            dt.Columns.Add(FullFilePathcolumn);

            DataColumn DateCreatedcolumn = new DataColumn();
            DateCreatedcolumn.DataType = System.Type.GetType("System.String");
            DateCreatedcolumn.ColumnName = "Date Created";
            dt.Columns.Add(DateCreatedcolumn);

            DataColumn Datemodifiedcolumn = new DataColumn();
            Datemodifiedcolumn.DataType = System.Type.GetType("System.String");
            Datemodifiedcolumn.ColumnName = "Date modified";
            dt.Columns.Add(Datemodifiedcolumn);

            foreach (string FullFilePath in array)
            {
                DataRow row = dt.NewRow();

                row[2] = Path.GetFileName(FullFilePath);
                row[3] = FullFilePath;
                row[4] = File.GetCreationTime(FullFilePath);
                row[5] = File.GetLastWriteTime(FullFilePath);

                dt.Rows.Add(row);
            }

            dt.Load(OraReader);
            DataView view = new DataView(dt);
            DGV_PatchStatus.DataSource = view;
        }
        FileCount.Text = "File Count ( " + DGV_PatchStatus.Rows.Count.ToString() + " )";
    }
    catch (Exception ex)
    {
        MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
    }
}

enter image description here

2 个答案:

答案 0 :(得分:1)

您可以使用DataTable.NewRow方法将行添加到DataTable

foreach (string FullFilePath in array)
{
    DataRow r = DT.NewRow();

    r[0] = Path.GetFileName(FullFilePath);
    r[1] = FullFilePath;
    r[2] = File.GetCreationTime(FullFilePath);
    r[3] = File.GetLastWriteTime(FullFilePath);
}

然后只需将DT再次绑定为DataSource

DGV_PatchStatus.DataSource = DT;

修改

  

我真正需要的是每个办公室都有文件列表

如果每个办公室行都有多个文件,那么您应该查看Tree-View-Tutorial这可能对实现所需结果有帮助。

这里也是Nested-DataGrid-Example也可能有所帮助。祝你好运。

答案 1 :(得分:0)

Make class为数据读取数据后,将数据分配给该对象,然后将对象放入List,然后将DGV_PatchStatus.DataSource初始化为该列表,当需要添加新行时,只需将数据对象添加到该列表并重新初始化DGV_PatchStatus DataSource