Question

现在，单击“添加”按钮时会弹出一个对话框。只要在对话框中按下提交按钮，它就会将其插入数据库。有2个字段，MR_ID和Supp_ID。 Supp_ID仅接受整数。我还想为Supp_ID添加更多验证，以便在输入的值是重复值并且已经在数据库中时它将不会提交或插入。我怎么能这样做？

JavaScript的：

$( function() {


    $("#insertButton").on('click', function(e){
    e.preventDefault();
  });   

    var dialog, form,

      mr_id_dialog = $( "#mr_id_dialog" ),
      supplier_id = $( "#supplier_id" ),
      allFields = $( [] ).add( mr_id_dialog ).add( supplier_id ),
      tips = $( ".validateTips" );
  console.log(allFields);

    function updateTips( t ) {
      tips
        .text( t )
        .addClass( "ui-state-highlight" );
      setTimeout(function() {
        tips.removeClass( "ui-state-highlight", 1500 );
      }, 500 );
    }

    function checkRegexp( o, regexp, n ) {
      if ( !( regexp.test( o.val() ) ) ) {
        o.addClass( "ui-state-error" );
        updateTips( n );
        return false;
      } else {
        return true;
      }
    }

   function addVendor() {
      var valid = true;
      allFields.removeClass( "ui-state-error" );
// ----- Validation for each input in add row dialog box -----
      valid = valid && checkRegexp( supplier_id, /^(0|[1-9][0-9]*)$/, "Please enter a valid Supplier ID" );
      console.log(allFields);
      if ( valid ) {
        var $tr = $( "#index_table tbody tr" ).eq(0).clone();
        var dict = {};
        var errors = "";
        $.each(allFields, function(){
          $tr.find('.' + $(this).attr('id')).html( $(this).val()+"-"+supplier_id );
          var type = $(this).attr('id');
          var value = $(this).val();
          console.log(type + " : " + value);
          // ----- Switch statement that provides validation for each table cell -----
          switch (type) {
            case "mr_id_dialog":
                dict["MR_ID"] = parseInt(value);
                console.log(dict['MR_ID']);
              break;
            case "supplier_id":
                dict["Supp_ID"] = value;
              break;
            }
        });
        $( "#index_table tbody" ).append($tr);
        dialog.dialog( "close" );
        console.log(dict);

        var request = $.ajax({
          type: "POST",
          url: "insert.php",
          data: dict
        });

        request.done(function (response, textStatus, jqXHR){
          if(JSON.parse(response) == true){
            console.log("row inserted");
          } else {
            console.log("row failed to insert");
            console.log(response);
          }
        });

        // Callback handler that will be called on failure
        request.fail(function (jqXHR, textStatus, errorThrown){
            console.error(
                "The following error occurred: "+
                textStatus, errorThrown
            );
        });

        // Callback handler that will be called regardless
        // if the request failed or succeeded
        request.always(function () {

        });


      }
      return valid;
    }

    var dialog = $( "#dialog-form" ).dialog({
      autoOpen: false,
      height: 400,
      width: 350,
      modal: true,
      buttons: {
        "Add Supplier ID": addVendor,
        Cancel: function() {
          dialog.dialog( "close" );
        }
      },
      close: function() {
        form[ 0 ].reset();
        allFields.removeClass( "ui-state-error" );
      }
    });

    form = dialog.find( "form" ).on( "submit", function( event ) {
      event.preventDefault();
      addVendor();
    });

    $( "#insertButton" ).button().on( "click", function() {
      dialog.dialog({
          position: ['center', 'top'],
          show: 'blind',
          hide: 'blind'
      });
      dialog.dialog("open");
    });
});

我的对话框的代码：

<div id="dialog-form" title="Add Supplier ID">
  <p class="validateTips">All form fields are required.</p>

<!-- Dialog box displayed after add row button is clicked -->
  <form>
    <fieldset>
      <label for="mr_id">MR_ID</label>
      <select name="mr_id" id="mr_id_dialog" class="text ui-widget-content ui-corner-all" value="300">
          <?php foreach($user1->fetchAll() as $user2) { ?>
            <option>
                <?php echo $user2['MR_ID'];?>
            </option>
        <?php } ?>
      </select><br><br>
      <label for="supplier_id">Supplier ID</label>
      <input type="text" name="supp_id" id="supplier_id" class="text ui-widget-content ui-corner-all" value="99">

      <!-- Allow form submission with keyboard without duplicating the dialog button -->
      <input type="submit" id="submit" tabindex="-1" style="position:absolute; top:-1000px">
    </fieldset>
  </form>
</div>

Answer 1

一旦用户离开该字段，您就可以向服务器发送ajax调用，并在数据库中检查是否存在具有相同值的任何记录。

如果是，则可以向用户抛出错误消息以使用不同的值。

将验证添加到输入字段以不允许重复条目

1 个答案: