我想在片段中创建一个带有图像视图的菜单。每个人都有抽屉菜单,所以我想要与众不同:
我制作了OneFragment.java,这是我的oncreateview:
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_one, container, false);
super.onViewCreated(view, savedInstanceState);
img = (ImageView)view.findViewById(R.id.imgRandom);
imageView9 = (ImageView)view.findViewById(R.id.imageView3);
imageView4 = (ImageView)view.findViewById(R.id.imageView4);
imageView5 = (ImageView)view.findViewById(R.id.imageView5);
imageView6 = (ImageView)view.findViewById(R.id.imageView6);
imageView7 = (ImageView)view.findViewById(R.id.imageView7);
imageView8 = (ImageView)view.findViewById(R.id.imageView8);
firstName = (TextView)view.findViewById(R.id.imie);
textView13 = (TextView)view.findViewById(R.id.textView13);
textView14 = (TextView)view.findViewById(R.id.textView15);
textView15 = (TextView)view.findViewById(R.id.textView16);
textView16 = (TextView)view.findViewById(R.id.textView17);
textView17 = (TextView)view.findViewById(R.id.textView18);
textView18 = (TextView)view.findViewById(R.id.textView19);
final Animation wbijam = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.wbijam);
textView13.startAnimation(wbijam);
final Animation wbijam1 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.wbijam);
textView14.startAnimation(wbijam1);
final Animation wbijam2 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.wbijam);
textView15.startAnimation(wbijam2);
final Animation wbijam3 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.wbijam);
textView16.startAnimation(wbijam3);
final Animation wbijam4 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.wbijam);
textView17.startAnimation(wbijam4);
final Animation wbijam5 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.wbijam);
textView18.startAnimation(wbijam5);
final Animation animShake = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.shak);
img.startAnimation(animShake);
final Animation load1 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.load1);
imageView9.startAnimation(load1);
final Animation load2 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.load2);
imageView4.startAnimation(load2);
final Animation load3 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.load3);
imageView5.startAnimation(load3);
final Animation load4 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.load4);
imageView6.startAnimation(load4);
final Animation load5 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.load5);
imageView7.startAnimation(load5);
final Animation load6 = AnimationUtils.loadAnimation(getActivity().getApplicationContext(), R.anim.load6);
imageView8.startAnimation(load6);
firstName.setText("Hey,"+" " +PreferenceConnector.readString(getActivity().getApplicationContext(), PreferenceConnector.FIRST_NAME, ""));
// Inflate the layout for this fragment
final ImageView img = (ImageView) view.findViewById(R.id.imgRandom);
// return view;
// ^^^^ error remove it
Resources res = getResources();
myString = res.getStringArray(R.array.myArray);
String q = myString[rgenerator.nextInt(myString.length)];
TextView tv = (TextView) view.findViewById(R.id.tv);
tv.setText(q);
// I have 3 images named img_0 to img_2, so...
final String str = "img_" + rnd.nextInt(9);
img.setImageDrawable
(
getResources().getDrawable(getResourceID(str, "drawable",
getActivity().getApplicationContext())
));
return view;
// ^^^ move it here
}
// I have 3 images named img_0 to img_2, so...
protected final static int getResourceID
(final String resName, final String resType, final Context ctx) {
final int ResourceID =
ctx.getResources().getIdentifier(resName, resType,
ctx.getApplicationInfo().packageName);
if (ResourceID == 0) {
throw new IllegalArgumentException
(
"No resource string found with name " + resName
);
} else {
return ResourceID;
}
}
}
我想点击一下
imageView9 = (ImageView)view.findViewById(R.id.imageView3);
将打开片段SecondFragment
有可能吗? 我尝试过,但没有找到任何解决方案。
答案 0 :(得分:0)
你可以发布你的布局吗? 当使用菜单在片段之间导航时,您将菜单保留在托管活动中,并通过切换该活动内的片段进行导航,无需将菜单放在其中一个片段中。