Question

="" I am trying to get value of href inside a div with class name(class="visible-xs"). I tried this code and it gets all the href outside div as well which I don't want.

$dom = new DOMDocument;
$dom->loadHTML($code2);
foreach ($dom->getElementsByTagName('a') as $node)
{

 echo $node->getAttribute("href")."\n";
}

Then i tried following but it gives me error(Fatal error: Call to undefined method DOMDocument::getElementsByClassName() in..):

$dom = new DOMDocument;
$dom->loadHTML($code2);
foreach ($dom->getElementsByClassName('visible-xs') as $bigDiv) {

   echo $bigDiv->getAttribute("href")."\n";
}

could any one help me fix the above error and only get the value of href inside div with class name visible-xs ?Thanks in advance.

sample data:

<tr class="ng-scope" ng-repeat="item in itemContent">
<td class="ng-binding" style="word-wrap: break-word;">test/folder/1.mp4
<div class="visible-xs" style="padding-top: 10px;">
<!-- ngIf: item.isViewable --> class="btn btn-default ng-scope" ng-click="$root.openView(item);">View</a><!-- end ngIf: item.isViewable -->
<a href="https://somesite.com/test/1.mp4" class="btn btn-default" ng-href="https://somesite.com/test/1.mp4" target="_blank">Download</a>
<a class="btn btn-default" href="javascript:void(0);" ng-click="item.upload()" target="_blank">Upload</a>
</div>
</td>
<!-- ngIf: hasViewables --><td class="text-right hidden-xs ng-scope" style="white-space: nowrap; width: 60px;" ng-if="hasViewables">
<!-- ngIf: item.isViewable -->class="btn btn-default ng-scope" ng-click="$root.openView(item);">View</a><!-- end ngIf: item.isViewable -->
</td><!-- end ngIf: hasViewables -->
<td class="text-right hidden-xs" style="white-space: nowrap; width: 250px;">
<a href="https://somesite.com/test/1.mp4" class="btn btn-default" ng-href="https://somesite.com/test/1.mp4" target="_blank">Download</a>
javascript:void(0);" ng-click="item.upload()" target="_blank">Upload</a>
</td>
</tr>

Answer 1

没有getElementsByClassName功能。迭代你的div，检查课程，如果匹配拉动里面的链接并输出你想要的href（如果你想在第一场比赛后停止，则打破）。

$dom = new DOMDocument;
libxml_use_internal_errors(true);
$dom->loadHTML($html);
libxml_clear_errors();
foreach ($dom->getElementsByTagName('div') as $div) {
     if($div->getattribute('class') == 'visible-xs') {
          foreach($div->getElementsByTagName('a') as $link) {
               echo $link->getattribute('href');
          }
     }
}

演示：https://eval.in/698484

break，https://eval.in/698488。

的示例

如何<a href="value" inside="" div="" with="" class="" name="" only?=""

1 个答案: