Question

伙计们正试图在我的模型中的字段中过滤重复项

例如我的模型是：

class Household(models.Model):
    office = models.ForeignKey(
        Office,
        related_name='households',
        help_text=_('The office that manages this data'),
    )

    uuid = UUIDField(
        auto=True,
        version=4,
        help_text=_('Unique identifier for each household'),
    )
    name = models.CharField(
        _('Family Name'),
        max_length=255,
        help_text=_('Name by which the household goes by'),
        db_index=True

class Person(models.Model):
    uuid = UUIDField(auto=True, version=4, help_text=_('unique id'))

    last_name = models.CharField(_("Last name"), max_length=255, help_text=_('last name'), db_index=True)
    first_name = models.CharField(_("First name"), max_length=255, blank=True, null=True, help_text=_('first name'))
    middle_name = models.CharField(_("Middle name"), max_length=255, blank=True, null=True, help_text=_('middle name'))
    location = models.ForeignKey(Location, verbose_name=_('Location'), help_text=_('location'))
 household = models.ForeignKey(
        Household,
        related_name='active_or_inactive_members',
        blank=True,
        null=True,
        verbose_name=_("Household"),
        help_text=_('Household')
    )

我正在使用此查询来获取一个家庭中的所有重复人员：

首先过滤办公室中的所有家庭

households = Household.objects.filter(office='so-co')

然后我遍历这些家庭以过滤具有重复ID的人

for household in households:
    persons = Person.objects.values('last_name').annotate(Count('id')).order_by().filter(id__count__gt=1)
    for person in persons:
        print person

问题是我的查询集正在打印所有人，我在这里错过了什么？

Answer 1

您没有在for循环中过滤household。您可能会使用Persons

获得与家庭相关的related_name

persons = household.active_or_inactive_members.all()

要查找last_name上的重复项：

persons = household.active_or_inactive_members.values('last_name')...... # your code here

在django中过滤带有重复项的字段

1 个答案: