Question

当我尝试这段代码时：

$query = '';
foreach ($data as $row)
{
    $where = array(
                'community_id'  => $row->id,
                'user_id'       => $this->session->user_id,
                'status'        => 'invited_to_join',
            );
    $update = array(
                'status' => 'joined',
            );
    $query .= $this->db->set($update)->where($where)->get_compiled_update('community_members').'; ';
}
if ($query)
{   
    return $this->db->query($query);
}

它给了我错误：

您的SQL语法有错误;检查手册对应于您的MariaDB服务器版本，以获得正确的语法接近＆＃39;更新community_members设置status =＆＃39;加入＆＃39;哪里 community_id =＆＃39; 18＆＃39;甲＆＃39;在第4行

this answer使用CASE直接查询，但我不知道如何将其转换为Codeigniter的查询生成器。

Answer 1

试试这个例子;

你可以像这样直接使用数组$data['id']，不需要在这里使用循环作为我的opine

        $this->db->set('status','joined');
        $this->db->where('community_id',$data['id']);
        $this->db->where('user_id',$this->session->user_id); 
        $this->db->where('status','invited_to_join');
        $this->db->update('community_members');

Answer 2

您也可以这样使用$where = "'community_id'=".$data['id']." AND user_id=".$this->session-user_id." AND status='invited_to_join'"; $this->db->set('status','joined'); $this->db->where($where); $this->db->update('community_members');子句：

const Schema = new GraphQLObjectType({
  name: "Mutation",
  description: "Mutation schema",
  fields() {
    return {
      // Add user
      addUser: {
        type: UserSchema,
        args: () => {
          return {
            firstName: {
             type: GraphQLString
            }
          };
        },
        resolve(_, args){
          return Db.models.user.update( () => {
            return _.mapValues(args, (v, k) => {
              return args[k];
            });
          }, {
            returning: true
          });
        }
      }

    };
  }
});

谢谢!!!

codeigniter使用多个where子句更新多行

2 个答案: