Question

这是我的代码

var filter1 = { id: 96, name: "Affinity Groups Allowed In Site",typeId: 74, description: "SiteAffinityGroupsAllowed" };

var filter2 = { id: 125, name: "AffinityLob", typeId: 100, description: "AffinityLob" };

$scope.filterCriteriaObjets = [filter1, filter2];

我正在尝试使用ng-model获取名称，但似乎ng模型正在获取整个对象。这是我的下拉列表

<select class="form-control" name="role" ng model="filterCriteria.ObjectName"
ng-options="item as item.name for item in filterCriteriaObjets" ng-required="true" ng-change="getObjectInfo()">
<option value="">- Select Filter Name -</option>
</select>

但是当我更改选项filterCriteria.ObjectName时，获取整个对象。我希望ng-model只等于name属性

Answer 1

这是你可以做的......

list = ['-1','2','+']
result=[]
for i in list:
        if '-' in i:
                result.append(i.replace('-','').isdigit())
        else:
                result.append(i.isdigit())

Answer 2

您的错误声明ng-model您将其声明为ng model

＆＃13;

<!DOCTYPE html>
<html ng-app="plunker">

  <head>
    <meta charset="utf-8" />
    <title>AngularJS Plunker</title>
    <script>document.write('<base href="' + document.location + '" />');</script>
    <link rel="stylesheet" href="style.css" />
    <script data-require="angular.js@1.4.x" src="https://code.angularjs.org/1.4.12/angular.js" data-semver="1.4.9"></script>
    <script src="app.js"></script>
  </head>

  <body ng-controller="MainCtrl">
    <p>Hello {{name}}!</p>
    <select class="form-control" name="role" ng-model="filterCriteria.ObjectName"
    ng-options="item.name as item.name for item in filterCriteriaObjets" ng-required="true" ng-change="getObjectInfo()">
    <option value="">- Select Filter Name -</option>
    </select>
    
  </body>
<script>
  var app = angular.module('plunker', []);

app.controller('MainCtrl', function($scope) {
  $scope.name = 'World';
  var filter1 = { id: 96, name: "Affinity Groups Allowed In Site",typeId: 74, description: "SiteAffinityGroupsAllowed" };

var filter2 = { id: 125, name: "AffinityLob", typeId: 100, description: "AffinityLob" };

$scope.filterCriteriaObjets = [filter1, filter2];

});

  </script>
</html>

＆＃13;

ng-model使用ng-options获取属性值

2 个答案: