Question

我使用像这样的枢轴

SELECT * FROM
(
  SELECT STUDENT_NAME,subject_code ,TERM_I_GRADE  FROM tablename
)
PIVOT
(
 TERM_I_GRADE 
  FOR subject_code IN (2001,2002)
)
ORDER BY STUDENT_NAME;

std_code Student_Name  subject_code    TERM_I_GRADE  
9        Kishan        2003            A
9        Kishan        2001            A
9        Kishan        2002            A
9        Kishan        2007            A
9        Kishan        2004            A

output 
-------------------
stdcode Student_Name  2003  2001  2002  2007 2004 
9       Kishan        A      A    A     A    A

Answer 1

select  *
from    mytable pivot (max(TERM_I_GRADE) for subject_code in (2003,2001,2002,2007,2004)) p

+----------+--------------+------+------+------+------+------+
| STD_CODE | STUDENT_NAME | 2003 | 2001 | 2002 | 2007 | 2004 |
+----------+--------------+------+------+------+------+------+
| 9        | Kishan       | A    | A    | A    | A    | A    |
+----------+--------------+------+------+------+------+------+

Answer 2

SELECT YEAR_CODE，＆＃39; HAVALGA＆＃39; AS School_Name，class_code，STUDENT_CODE，STUDENT_NAME，KANNADA，ENGLISH，HINDI，MATHS，SCIENS，SOCIAL，EVS来自（选择 YEAR_CODE，class_code，STUDENT_CODE，STUDENT_NAME， SUBJECT_CODE，TERM_I_GRADE为TERM_I_GRADE 来自SRSDF_EXAM_TERM_I WHERE
SCHOOL_CODE = 1301和YEAR_CODE =＆＃39; 2016-2017＆＃39;

） PIVOT（MAX（TERM_I_GRADE）FOR SUBJECT_CODE IN（2001 AS KANNADA，2002 AS ENGLISH， 2003 AS HINDI，2004 AS MATHS， 2005 AS ASS，2006 AS SOCIAL， 2007 AS EVS）） ORDER BY class_code，STUDENT_CODE;

在Oracle中使用PIVOT运算符

2 个答案: