Laravel现有验证

Question

如果插入中的client_id来自另一个表

，我想验证输入

如果现有

，则选择 client_id 的表格

Schema::create('cluster_members', function (Blueprint $table) {
            $table->increments('id');
            $table->integer('cluster_id')->unsigned()->nullable();
            $table->integer('client_id')->unsigned()->nullable();
            $table->softDeletes();
            $table->timestamps();

});

表格，如果通过验证，我将插入记录

Schema::create('loan_applications', function (Blueprint $table) {
            $table->increments('id');
            $table->integer('client_id')->unsigned()->index();
            $table->integer('product_id')->unsigned()->index();


});

所以在我的控制器中

这是我的规则

$rule = ['client_id'=>'required | numeric | exists:clients,id | exists:cluster_members,client_id'];

这会引发我的错误

SQLSTATE [42S22]：未找到列：1054'where子句'中的未知列'id'