Question

是否有一种简单的方法来订购此数组（日期将始终以正确的顺序显示）

  0 => "Thursday,Sunday"
  1 => "Tuesday"
  2 => "Monday"
  3 => "Tuesday,Thursday,Saturday"
  4 => "Tuesday"
  5 => "Monday,Wednesday"
  6 => "Saturday,Sunday"
  8 => "Wednesday"
  9 => "Saturday"
  10 => "Tuesday"
  11 => "Monday,Sunday"

按此顺序（按星期几）

  2 => "Monday"
  5 => "Monday,Wednesday"
  11 => "Monday,Sunday"
  1 => "Tuesday"
  4 => "Tuesday"
  10 => "Tuesday"
  3 => "Tuesday,Thursday,Saturday"
  7 => "Tuesday,Friday"
  8 => "Wednesday"
  0 => "Thursday,Sunday"
  9 => "Saturday"
  6 => "Saturday,Sunday"

最后，我需要定义开始日期，但希望能够很容易地概括解决方案。

谢谢！

更新

下一个问题是如何重新排列

    $day_map = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'];

从今天开始date('l')。所以如果今天的Fridey我会得到

    $rearranged_day_map = ['Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday'];

更新问题的答案（原问题的答案如下）：

    //days
    $day_map = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'];
    //order days to start from tomorrow
    $today = date('N'); // get today's day of the week
    $day_map_rearranged = array_merge(array_slice($day_map, $today),array_slice($day_map, 0, $today));

Answer 1

正如其他人所建议的那样，你需要使用uasort这个。我首先要做的是explode字符串。然后为日序列（周一至周五）创建默认映射，并将其用于排序。

这是一个肮脏的想法：

// default order
$day_map = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday'];
uasort($input_array, function($a, $b) use ($day_map) {
    $c = explode(',', $a); $d = explode(',', $b);
    for($i = 0, $len = count($c); $i < $len; $i++) {
        $d1 = @array_search($c[$i], $day_map);
        $d2 = @array_search($d[$i], $day_map);
        if($d1 == $d2) {
            continue; // skip, check the next column
        }
        return $d1 - $d2;
    }
});

Sample Out

Answer 2

试试这个。

$roster = array(
0 => "Thursday,Sunday",
1 => "Tuesday",
2 => "Monday",
3 => "Tuesday,Thursday,Saturday",
4 => "Tuesday",
5 => "Monday,Wednesday",
6 => "Saturday,Sunday",
8 => "Wednesday",
9 => "Saturday",
10 => "Tuesday",
11 => "Monday,Sunday");

$day = array(
0 => "Monday",
1 => "Tuesday",
2 => "Wednesday",
3 => "Thursday",
4 => "Friday",
5 => "Saturday",
6 => "Sunday"); 

$result = array();

$x=0;
foreach($day as $idx => $arrValue){

    foreach($roster as $idxRoster => $arrRoster){
        $list = explode(',', $arrRoster);
        if($list[0] == $arrValue){
            $result[$x]['id'] = $idxRoster;
            $result[$x]['val'] = $arrRoster;

            $x++;
        }// end if
    }// end foreach

}// end foreach

echo "<pre>";
print_r($result);

php，按值排序数组（星期几）

2 个答案: