Question

我有一个数据框（下面），列'name'，我想删除（例如第一行）

'/Users/xccxken/Desktop/NNRelease/paperVersion/'

和

'.txt'

保持单词（第一行示例）

'Topic+Topic_of_Situation.shortageglut'

每行

,n_1,n_2,name
0,water,shortage,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Situation.shortageglut.txt
1,supply,shortage,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Situation.shortageglut.txt
2,skill,shortage,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Situation.shortageglut.txt
214,income,policy,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.rules.legal.txt
215,immigration,policy,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.rules.legal.txt
216,health,policy,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.rules.legal.txt
485,license,agreement,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.deal.txt
486,lease,agreement,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.deal.txt
487,immunity,agreement,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.deal.txt
488,franchise,agreement,/Users/xccxken/Desktop/NNRelease/paperVersion/Topic+Topic_of_Plan&Deal&Rules.deal.txt

Answer 1

您可以使用.str.strip()方法：

prefix = '/Users/xccxken/Desktop/NNRelease/paperVersion/'
suffix = '.txt'
df['name'] = df['name'].str.rstrip(suffix).str.lstrip(prefix)

或正则表达式：

description = r'([^/]+)\.txt'
df['name'] = df['name'].str.extract(description)

python：读取具有文件名和文件概念的文件夹

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