Question

我打算做的是有一个剩余订单列，这将是以下计算的结果： [orderedvalue] - [totaljobvalue]

select [orderedvalue] = sum([ordervalue]), 
       jobtype,
       [totaljobvalue] = (select sum([total value]) 
                          from job 
                          where jobType = quotetrackerorders.jobType 
                          and reference like '%40330%')
from quotetrackerorders
where quoteref like '%40330%'
group by jobtype

我尝试过以下代码：

select [orderedvalue] = sum([ordervalue]), 
       jobtype,
       [totaljobvalue] = (select sum([total value]) 
                          from job 
                          where jobType = quotetrackerorders.jobType 
                          and reference like '%40330%'),
       [orderremaining] = [orderedvalue] - [totaljobvalue]
from quotetrackerorders
where quoteref like '%40330%'
group by jobtype

但是这不起作用，因为它不会将任何别名识别为列...我该怎么做才能实现以下结果：

JobType =壁画
Orderedvalue = 311654（示例值）
TotalJobvalue = 3446（示例值）
OrderRemaining = 64654（示例值）

您知道如何让SQL将这些别名识别为列吗？

Answer 1

考虑以下

Select A.*
      ,SomeName = [orderedvalue] - [totaljobvalue]
 From (
        Select [orderedvalue] = sum([ordervalue])
              , jobtype
              , [totaljobvalue] = (select sum([total value]) 
                                   from job 
                                   where jobType = quotetrackerorders.jobType 
                                   and reference like '%40330%')
        from quotetrackerorders
        where quoteref like '%40330%'
        group by jobtype
) A

尝试使用别名Transact Sql时出现无效的列名错误

1 个答案: