akka-http如果失败则响应传出响应

Question

我正在调用外部API，如果状态代码不是确定，我希望将结果“按原样”返回给用户：

1,Formerly free software
2,Formerly proprietary software
3,Freeware
4,Oracle software
5,Proprietary cross-platform software
6,Proprietary database management systems
7,Proprietary operating systems
8,Proprietary version control systems
9,Proprietary wiki software
10,Shareware
11,VMware
12,Warez

如果状态代码不是OK，我怎样才能“原样”返回响应而不执行以下操作：

val connectionFlow: Flow[HttpRequest, HttpResponse, Future[Http.OutgoingConnection]] =
  Http().outgoingConnection("akka.io")
def responseFuture: Future[HttpResponse] =
  Source.single(HttpRequest(uri = "/"))
    .via(connectionFlow)
    .runWith(Sink.head)

val fooRoutes = path("foo"){
get {
complete(
responseFuture.flatMap{ response =>
case OK => 
Unmarshal(response.entity.withContentType(ContentTypes.`application/json`)).to[Foo]
case _ => response //fails 
})}}

Answer 1

我认为可能有不同的有效解决方法，可以使用onComplete指令：

  val fooRoutes = path("foo"){
    get {
      onComplete(responseFuture) {
        case Success(response) if response.status == OK =>
          complete(Unmarshal(response.entity.withContentType(ContentTypes.`application/json`)).to[Foo])

        case Success(response) => complete(response)
        case Failure(ex)    => complete((InternalServerError, s"An error occurred: ${ex.getMessage}"))
      }
    }
  }