Question

我有一个1.txt：

I. Introduction to Text Mining 1
I.1 Defining Text Mining 1
I.2 General Architecture of Text Mining Systems 13

II. Core Text Mining Operations 19
II.1 Core Text Mining Operations 19
II.2 Using Background Knowledge for Text Mining 41
II.3 Text Mining Query Languages 51

III. Text Mining Preprocessing Techniques 57
III.1 Task-Oriented Approaches 58
III.2 Further Reading 62

IV. Categorization 64
IV.1 Applications of Text Categorization 65
IV.2 Definition of the Problem 66
IV.3 Document Representation 68

我想得到这样的结果：

I. Introduction to Text Mining 1.1
    I.1 Defining Text Mining 1.1
    I.2 General Architecture of Text Mining Systems 13.1

II. Core Text Mining Operations 19.1
    II.1 Core Text Mining Operations 19.1
    II.2 Using Background Knowledge for Text Mining 41.1
    II.3 Text Mining Query Languages 51.1
...

两个变化：

1. I I.1 use the TAB.
2. all number in the end plus 0.1

我尝试使用熊猫，但它不起作用。我尝试其他方式，但我不知道如何编写下一个程序：

# -*- coding: utf-8 -*-
import re

f=open("D:/Downloads/1.txt")
page_list = []
content=[]
for line in f:
    if re.search('(\d+)$',line) !=None:
        page_list.append(re.search('(\d+)$',line).group())
    if re.search('^(.*\.\d+)',line) !=None:
        content.append(re.search('^(.*\.\d+)',line).group())
str=map(lambda x:x+'.1',page_list)
print str
con=map(lambda x:'\t'+x,content)
print con

该计划的结果：

['1.1', '1.1', '13.1', '19.1', '19.1', '41.1', '51.1']
['\tI.1', '\tI.2', '\tII.1', '\tII.2', '\tII.3']

Answer 1

你可以试试这个：

\1\2.1

并替换为：

import re

regex = r"(.*)(\d+)"

test_str = ("I. Introduction to Text Mining 1\n"
    "I.1 Defining Text Mining 1\n"
    "I.2 General Architecture of Text Mining Systems 13\n\n"
    "II. Core Text Mining Operations 19\n"
    "II.1 Core Text Mining Operations 19\n"
    "II.2 Using Background Knowledge for Text Mining 41\n"
    "II.3 Text Mining Query Languages 51\n\n"
    "III. Text Mining Preprocessing Techniques 57\n"
    "III.1 Task-Oriented Approaches 58\n"
    "III.2 Further Reading 62\n\n"
    "IV. Categorization 64\n"
    "IV.1 Applications of Text Categorization 65\n"
    "IV.2 Definition of the Problem 66\n"
    "IV.3 Document Representation 68\n\n")

subst = "\\1\\2.1"


result = re.sub(regex, subst, test_str, 0, re.MULTILINE)

if result:
    print (result)

Explanation

示例代码：

I. Introduction to Text Mining 1.1
I.1 Defining Text Mining 1.1
I.2 General Architecture of Text Mining Systems 13.1

II. Core Text Mining Operations 19.1
II.1 Core Text Mining Operations 19.1
II.2 Using Background Knowledge for Text Mining 41.1
II.3 Text Mining Query Languages 51.1

III. Text Mining Preprocessing Techniques 57.1
III.1 Task-Oriented Approaches 58.1
III.2 Further Reading 62.1

IV. Categorization 64.1
IV.1 Applications of Text Categorization 65.1
IV.2 Definition of the Problem 66.1
IV.3 Document Representation 68.1

示例输出：

{{1}}

Answer 2

对于TAB缩进，您可以使用以下代码：

for m in re.finditer(r'[IVX]+\.\d.*\n',result):
  oldgroup = m.group()
  newgroup = '\t' + oldgroup
  result = re.sub(oldgroup,newgroup,result)

python正则表达式txt

2 个答案: