所以我有这个模板利用KendoUI渲染网格。这是其中的一部分:
<script id="rowTemplateCourse" type="text/x-kendo-tmpl">
<tr data-cid="#: id #" class="course-row" id="course-row#: id #">
<td>
<span class="circle-indicator label-#if(package_is_active == 1){#success#}else{#danger#}#"></span>
</td>
<td>
#: course_name # - #= name#
</td>
<td>
<span class="badge element-bg-color-blue">ver. #:version_number#</span>
</td>
</tr>
</script>
我从php控制器获取所需信息,该控制器在我的视图中加载一个包含此模板的变量。变量包含这种数据:
[1] => Array(
[id] => 544
[course_name] => Course for whatever
[price] => 52
[logo] => assets/images/new_course.png
[version_number] => 1
[parent_version_id] => 0
[course_price] => 52.00
[description_for_school] =>
[is_print_only] => 0
[offer_pdf] => 0
[pdf_final_price] => 0.00
[simple_course] => 0
[state_id] => 50
[name] => Tennessee
[cs_days_to_complete] => 120
[course_is_active] => 1
[user_in_course] => no
[user_is_waiting] => no
[days_to_complete] => 0)
在我看来,我像这样解析这个变量:
var course_data = JSON.parse('<?php print(json_encode($courses));?>');
这样可以正常工作并返回相同的数据(从console.log复制):
1: Object
course_is_active:"1"
course_name:"Course for whatever"
course_price:"52.00"
cs_days_to_complete:"120"
days_to_complete:0
description_for_school:""
id:"544"
is_print_only:"0"
logo:"assets/images/new_course.png"
name:"Tennessee"
offer_pdf:"0"
parent_version_id:"0"
pdf_final_price:"0.00"
price:"52"
simple_course:"0"
state_id:"50"
user_in_course:"no"
user_is_waiting:"no"
version_number: "1"
我将数据加载到网格中,如下所示:
var courses_grid = $("#courses_grid").kendoGrid({
dataSource: {
data: course_data,
schema: {
model: {
fields: {
id: {
type: "number"
},
course_name: {
type: "string"
},
course_short_description: {
type: "string"
}
}
}
},
pageSize: 10,
},
toolbar: kendo.template($("#course-header-template").html()),
rowTemplate: kendo.template($("#rowTemplateCourse").html()),
groupable: false,
sortable: true,
selectable: "single",
pageable: {
refresh: true,
pageSizes: true,
buttonCount: 5
},
columns: [{
title: "Status",
width: 100
}, {
title: "Course Name",
}]
});
当页面加载时,我收到一个错误,即没有定义course_is_active。我不知道它是如何定义的,因为它显然在这里并具有价值。有人可以帮我解决这个问题吗?
有关错误的更多信息:
Uncaught ReferenceError: course_is_active is not defined
(function(data
/**/) {
var $kendoOutput, $kendoHtmlEncode = kendo.htmlEncode;with(data){$kendoOutput='\n\t <tr data-cid="'+$kendoHtmlEncode( id )+'" class="course-row" id="course-row'+$kendoHtmlEncode( id )+'">\n <td>\n <span class="circle-indicator label-';if(course_is_active == 1){;$kendoOutput+='success';}else{;$kendoOutput+='danger';};$kendoOutput+='"></span>\n </td>\n\t\t <td>\n '+$kendoHtmlEncode( course_name )+' - '+( name)+'\n\t\t </td>\n\t\t\t<td>\n <span class="badge element-bg-color-blue">ver. '+$kendoHtmlEncode(version_number)+'</span>\n\t\t </td>\n\t </tr>\n\n';}return $kendoOutput;
})
答案 0 :(得分:1)
我发现了这个问题。在我的PHP代码中,如果值等于0,我正在检查数组,如果是,我将从数组中删除该元素。这恰好是我在视图中加载的2D数组中的第一个元素,因此当KendoUI开始在表中加载变量时,它以[0]索引开始,该索引不存在,并抛出错误。感谢所有参与的人。