说,我有一张表"开始"日期
ID Start
1 null
2 2001-1-1
3 2002-1-1
现在,我需要以有效的方式计算每条记录的有效时间范围:
ID Start Finish
1 null 2000-12-31
2 2001-1-1 2001-12-31
3 2002-1-1 null
答案 0 :(得分:2)
使用LEAD:
create table #dates
(
ID int,
Start date
)
insert into #dates values(1,null),(2,'01-jan-2001'),(3,'01-jan-2002')
select ID,
Start,
DATEADD(DD, -1, LEAD(Start,1) over (order by Start)) AS Finish
from #dates
答案 1 :(得分:0)
使用JOIN
。
<强>查询强>
select t1.[ID], t1.[Start],
dateadd(day, -1, t2.[Start]) as [Finish]
from [your_table_name] t1
left join [your_table_name] t2
on t1.ID = t2.ID - 1;
<强> Demo 1
强>
正如HABO所提到的,如果Id的顺序不正确。然后按ID
列提供行号。
<强>查询强>
;with cte as(
select [row_num] = row_number() over(
order by [ID]
),*
from [your_table_name]
)
select t1.[ID], t1.[Start],
dateadd(day, -1, t2.[Start]) as [Finish]
from cte t1
left join cte t2
on t1.[row_num] = t2.[row_num] - 1;
<强> Demo 2
强>