Question

我正在使用azure移动应用程序，它返回的json数据格式无法读取。使用

获取刺痛

var newMember = new Member() { Id = Settings.UserId };
var url = azureService.Client.MobileAppUri + ".auth/me";
var client = new HttpClient();
client.DefaultRequestHeaders.Add("X-ZUMO-AUTH", Settings.AuthToken);
var response = await client.GetAsync(new Uri(url));
response.EnsureSuccessStatusCode();
dynamic responseBody = await response.Content.ReadAsStringAsync();

responseBody是

"[
  {
    \"id_token\": \"tokenstring\",
    \"provider_name\": \"aad\",
    \"user_claims\": [
      {
        \"typ\": \"exp\",
        \"val\": \"903i4231\"
      },
      {
        \"typ\": \"nbf\",
        \"val\": \"123516345294\"
      },
      {
        \"typ\": \"ver\",
        \"val\": \"1.0\"
      },
      {
        \"typ\": \"iss\",
        \"val\": \"https: \\\/\\\/login.microsoftonline.com\\\/somestring\\\/v2.0\\\/\"
      },
      {
        \"typ\": \"http: \\\/\\\/schemas.xmlsoap.org\\\/ws\\\/2005\\\/05\\\/identity\\\/claims\\\/nameidentifier\",
        \"val\": \"someotherstring\"
      },
      {
        \"typ\": \"aud\",
        \"val\": \"anotherstringstill\"
      },
      {
        \"typ\": \"nonce\",
        \"val\": \"stringy\"
      },
      {
        \"typ\": \"iat\",
        \"val\": \"3543345\"
      },
      {
        \"typ\": \"http: \\\/\\\/schemas.microsoft.com\\\/ws\\\/2008\\\/06\\\/identity\\\/claims\\\/authenticationinstant\",
        \"val\": \"6363456345\"
      },
      {
        \"typ\": \"http: \\\/\\\/schemas.xmlsoap.org\\\/ws\\\/2005\\\/05\\\/identity\\\/claims\\\/givenname\",
        \"val\": \"FIRSTNAME?\"
      },
      {
        \"typ\": \"http: \\\/\\\/schemas.xmlsoap.org\\\/ws\\\/2005\\\/05\\\/identity\\\/claims\\\/surname\",
        \"val\": \"LastName?\"
      },
      {
        \"typ\": \"http: \\\/\\\/schemas.microsoft.com\\\/identity\\\/claims\\\/identityprovider\",
        \"val\": \"google.com\"
      },
      {
        \"typ\": \"http: \\\/\\\/schemas.microsoft.com\\\/identity\\\/claims\\\/objectidentifier\",
        \"val\": \"somestringelse\"
      },
      {
        \"typ\": \"emails\",
        \"val\": \"address@gmail.com\"
      },
      {
        \"typ\": \"tfp\",
        \"val\": \"B2C_1_ScoreSignupIn\"
      }
    ],
    \"user_id\": \"useridstring\"
  }
]"

如何将其转换为有用的C＃对象，以便我可以获取字符串Firstname?和LASTNAME?

我试过

string firstName = responseJson.claims.givenname;

无济于事。此外，这种类型的JSON叫什么。我记得在学习azure API时阅读它，但我不记得在哪里。我甚至不知道该怎么称它来搜索它。还有jsonprettyprint.com处的json prettyprints，但我无法使用http://json2csharp.com/将其转换为C＃对象

Answer 1

你可以Install-Package Newtonsoft.Json，然后你就可以从JSON中找到值了

string jsn = File.ReadAllText("YourJSON.txt");
List<RootObject> ro = JsonConvert.DeserializeObject<List<RootObject>>(jsn);
foreach(UserClaim uc in ro[0].user_claims)
{
    if(uc.val=="FIRSTNAME")
    {
        //Do whatever you want.
    }
    //or
    if(uc.typ.Contains("givenname"))
    {
        Console.WriteLine(uc.val);
    }


}

这将是您的JSON的类

public class UserClaim
{
    public string typ { get; set; }
    public string val { get; set; }
}

public class RootObject
{
    public string id_token { get; set; }
    public string provider_name { get; set; }
    public List<UserClaim> user_claims { get; set; }
    public string user_id { get; set; }
}

Answer 2

请试试这个

JavaScriptSerializer serializer = new JavaScriptSerializer(); 

dynamic item = serializer.Deserialize<object>("{ \"test\":\"some data\" }");

string test= item["test"];

替换此

“{\”test \“：\”some data \“}”

使用您的JSON字符串。

您还可以指定确切的数据类型，而不是对象和动态变量。

如何从C＃中的api解析奇怪的json对象

2 个答案: