Question

我传入一个字符串变量来打开webview中的url，当我根据字符串创建url时，它不会解包。我不确定我做错了什么。这是代码：

class WebViewController: UIViewController, WKUIDelegate {

var urlString:String?
var vehicle:Vehicle?
var theUrlString = "http://www.ksl.com/auto/search/" //This variable is set in the prepareForSegue in a previous view controller. It is set correctly

var webView: WKWebView!


override func loadView() {
    let webConfiguration = WKWebViewConfiguration()
    webView = WKWebView(frame: .zero, configuration: webConfiguration)
    webView.uiDelegate = self
    view = webView
    if let urlStri = urlString {
        print("url is " + urlStri)
        theUrlString = urlStri
    }else {

    }

}

override func viewDidLoad() {
    super.viewDidLoad()

    print("theUrlString is " + theUrlString) // this correctly prints: theUrlString is http://www.ksl.com/auto/search/index?keyword=&make%5B%5D=Chevrolet&model%5B%5D=Silverado 1500&yearFrom=2006&yearTo=2008&mileageFrom=&mileageTo=&priceFrom=&priceTo=&zip=&miles=25&newUsed%5B%5D=All&sellerType%5B%5D=&postedTime%5B%5D=&titleType%5B%5D=&body%5B%5D=&transmission%5B%5D=&cylinders%5B%5D=&liters%5B%5D=&fuel%5B%5D=&drive%5B%5D=&numberDoors%5B%5D=&exteriorCondition%5B%5D=&interiorCondition%5B%5D=&cx_navSource=hp_search
    if let url = URL(string: theUrlString){

        let myRequest = URLRequest(url: url) //In debugging, it never makes it inside the if statement here

        webView.load(myRequest)
    }


}

Answer 1

您的DELETE h -------^ FROM main_history h JOIN main_iteminstance i ON h.instance_id = i.id WHERE platform_type_id = 'vudu';编码不正确。因此，当您使用theUrlString时，它将返回URL(string:)（表示传入的URL字符串格式错误）。

我建议使用nil来创建您的网址。

类似的东西：

URLComponents

var urlComponents = URLComponents(string: "http://www.ksl.com/auto/search/index") var arguments: [String: String] = [ "keyword": "", "make": "Chevrolet", "model": "Silverado 1500" ] var queryItems = [URLQueryItem]() for (key, value) in arguments { queryItems.append(URLQueryItem(name: key, value: value)) } urlComponents?.queryItems = queryItems if let url = urlComponents?.url { print(url) // http://www.ksl.com/auto/search/index?keyword=&model=Silverado%201500&make=Chevrolet } API参考：https://developer.apple.com/reference/foundation/urlcomponents

Swift 3可选麻烦。无法用传入的字符串解包url

1 个答案: