我从.txt文件中引入值并将它们放入数组中,但最终存储在数组中的数字与文件中的数字不同,我不明白为什么或我该如何解决它。
文本文件使用这些值进行布局
2
20.0
10.0
100
将值导入文件的方法是:
//variables global to the class
public static int level;
public static int hp;
public static double vigor;
public static double intelligence;
public static void checkSaveState() throws IOException
{
//this method checks the save file for data
try
{
double[] savedGa = new double[4];
BufferedReader saveFile = new BufferedReader(new FileReader("HRHeroSaveGame.txt"));
for (int i = 0; i < 4; i++)
{
savedGa[i] = saveFile.read();
}
level = (int) savedGa[0];
vigor = savedGa[1];
intelligence = savedGa[2];
hp = (int) savedGa[3];
System.out.println("Level: " + level + " Vigor: " + vigor + " Intelligence: " + intelligence + " HP: " + hp);
} catch (FileNotFoundException e) {
System.out.println("Sorry, a save file couldn't be found for you.");
}
}
输出总是这样结束:
Level: 50 Vigor: 13.0 Intelligence: 10.0 HP: 50
以防这是相关的,这是创建文件的方法。
public static void saveGame() throws IOException
{
PrintWriter saveFile = new PrintWriter( new FileWriter("HRHeroSaveGame.txt"));
saveFile.println(level);
saveFile.println(vigor);
saveFile.println(intelligence);
saveFile.println(hp);
saveFile.close();
}
答案 0 :(得分:3)
read()
读取一个字符。这解释了您的结果:'2'
= 50,'\r'
= 13,'\n'
= 10
您必须将每行读作String
并解析它以获得双打:
savedGa[i] = Double.parseDouble(saveFile.readLine());
答案 1 :(得分:1)
BufferReader的read()方法读取char的整数表示,而不是完整的强制转换为double或int。
要解决此问题,只需将您的for循环更改为此
即可try
{
double[] savedGa = new double[4];
BufferedReader saveFile = new BufferedReader(new FileReader("C:/test.txt"));
for (int i = 0; i < 4; i++)
{
savedGa[i] = Double.parseDouble(saveFile.readLine());
}
level = (int) savedGa[0];
vigor = savedGa[1];
intelligence = savedGa[2];
hp = (int) savedGa[3];
System.out.println("Level: " + level + " Vigor: " + vigor + " Intelligence: " + intelligence + " HP: " + hp);
} catch (FileNotFoundException e) {
System.out.println("Sorry, a save file couldn't be found for you.");
}
这将整行读取为String,然后将其解析为double。