Question

我正在接受如下用户输入：0,1,2,3,5 用户可以写任何数字并用逗号分隔，输入将是x，y，z，k，c

然后我无法检查调用split（）之后的任何数字是0还是大于30.

代码段：

numbers = input(user[i]['name'] + 
", assign 10 different numbers between 1-30 (separate each with a comma ','): ")
        usrNums = numbers.split()

for number in usrNums:
    if number < 1 or number > 30: 
     #Something goes here, however, not important now.

P.S。我在all()

上读过一些内容

澄清：用户输入一些数字，例如0,5,2,9,7,10 调用usrNums = numbers.split() split()并将其存储在usrNums中，然后我想检查usrNums [0, 5, 2, 9, 7, 10]中的每个数字是否有＆＃34; 0表示数字＆lt; ; 1或＆gt; 30＆＃34 ;.

编辑：不，这不是重复，我通读，How can I read inputs as integers in Python?，它根本不是一样的。我的问题是用户输入带有逗号分隔的数字，而不是每个输入一个数字。

Answer 1

使用拆分时，数字的类型为字符串。要与1或30进行比较，将它们转换为整数

numbers  = "0,1,2,3,5"
usrNums = numbers.split(",")
#usrNums ["0","1","2","3","5"]
for number in usrNums:
    if int(number) < 1 or int(number) > 30:

Answer 2

numbers = "1,2,3,31"
for number in numbers.split(","):
    number = eval(number) # or use int(number) or float(number) as example
    if number < 1 or number > 30:
        #do something

你忘了＆＃34;，＆＃34;在split函数中忘记将字符串转换为整数。

Answer 3

您可以使用map()方法。

numberString = '1, 2, 3, 4, 5, 6, 7'
numbers = map(int, numberString.split(',')) # numbers = [1, 2, 3, 4, 5, 6, 7]
for num in numbers:
    if num < 1 or num > 30:
        # Do whatever you want here...

希望这有帮助！：）

Answer 4

输入是一个字符串。使用levelplot(projected_r)与eval进行比较：

int

您还需要指明如何拆分字符串：for number in usrNums: if eval(number) < 1 or eval(number) > 30: #Something goes here, however, not important now.

Python用户输入split（）和循环

4 个答案: