我有一个php变量值，我们必须在按钮点击时自动将它传递给脚本变量。请建议我。
Data当我点击按钮<?php
$query2 = mysql_query("select * from video_detail where video_id='$id' and status=1");
while( $qry2 = mysql_fetch_array($query2)){
$part1 = $qry2["part"];
$from1 = $qry2["from"];
$to1 = $qry2["to"];
?>
<button><? echo $part1;?></button><? }?><br>
<video style="border:1px solid" id="myVideo" width="320" height="176" controls>
<source src="uploads/videos/<?php echo $vid;?>" type="video/mp4">
</video>
<script>
var video = document.getElementById('myVideo');
var videoStartTime = 0;
var durationTime = 0;
video.addEventListener('loadedmetadata', function() {
videoStartTime = 2;
durationTime = 4;
this.currentTime = videoStartTime;
}, false);
video.addEventListener('timeupdate', function() {
if(this.currentTime > videoStartTime + durationTime){
this.pause();
}
});
</script>
传递给$from1 = ??的值时;并且videoStartTime值传递给$to1 = ??;
答案 0 :(得分：0)
做类似的事情：
<script>
var form1 = <?= $form1 ?>;
var to1 = <?= $to1 ?>;
</script>
在按钮中添加一个事件，如：
<button onclick="myFunction()">Click</button>
当onclick事件发生时，覆盖此函数内的值：
function myFunction(){
videoStartTime = form1;
durationTime = to1;
}