Question

我正在构建动态查询，而且我很难搞清楚这个错误代码：

错误：您的SQL语法出错;查看与您的MariaDB服务器版本对应的手册，以获得正确的语法，以便在＆＃39;＆＃39;＆＃39;＆＃39;品牌＆＃39;＆＃39;＆＃39;＆＃39;＆＃39;＆＃39;＆＃39;＆＃39; 39;类型＆＃39;，＆＃39; c型＆＃39;＆＃39; POE＆＃39;＆＃39;功能＆＃39;＆＃39;透镜＆＃39;＆＃39;价格＆＃39;）价值观（＆＃39; un＆＃39;第1行

这是我的PHP：

<?php
include("config.php");

$cameraCol = array("'image'", "'brand'", "'model'", "'type'", "'c-type'", "'poe'", "'specs'", "'lens'", "'price'");
$accessoriesCol = array("image", "brand", "model", "price");
$cableCol = array("image", "brand", "model", "type", "price");
$powerCol = array("image", "brand", "model", "channels", "price");
$recorderCol = array("image", "brand", "model", "type", "poe", "specs", "ports", "price");
$routerCol = array("image", "brand", "model", "wireless-capability", "price");
$switchCol = array("image", "brand", "model", "ports", "price");
$wirelessCol = array("image", "brand", "model", "frequency", "speed", "price");

$category = $_POST['category'];

if($category == "camera"){
    $cameraImp = implode(",", $cameraCol);
    $cameraVal = array("'".$_POST['image']."'", "'".$_POST['brand']."'", "'".$_POST['model']."'", "'".$_POST['type']."'", "'".$_POST['c-type']."'", 1, "'".$_POST['specs']."'", "'".$_POST['lens']."'", $_POST['price']);
    $cameraVal = implode(",", $cameraVal);
    insertItem($cameraImp, $category, $cameraVal);

}

function insertItem($columns, $category, $cameraValArr){
    include("config.php");
    $sql2 = "INSERT INTO ". $category ."(". $columns .") VALUES(". $cameraValArr .")";
    $result2 = mysqli_query($conn, $sql2);
    if(!$result2){
        die("Error: " . mysqli_error($conn));
    }
}
?>

这显然是我的查询中的一个错误，我很确定我错过了一些东西。任何帮助将不胜感激！

Answer 1

解决方案：从我的数据库中的列名中删除连字符，特别是＆＃34; c-type＆＃34;列。

PHP MySQL动态查询错误

1 个答案: