Question

我有两个多维数组：

第一阵比萨：

0 => array:2 [▼
    "pizza_id" => 11
    "pizza_name" => "Hawaï"
]
1 => array:2 [▼
    "pizza_id" => 12
    "pizza_name" => "Tonno"
]
2 => array:2 [▼
    "pizza_id" => 13
    "pizza_name" => "Surprise"
]

第二阵列成分：

0 => array:4 [▼
    "pizza_id" => 11
    "ingredient_one" => "Ananas"
    "ingredient_two" => "Onion"
    "ingredient_three" => "Ham"
]
1 => array:4 [▼
    "pizza_id" => 12
    "ingredient_one" => "Tuna"
    "ingredient_two" => "Onion"
    "ingredient_three" => null
]

我想合并这两个通过pizza_id链接它们的数组。其中一个Pizza Ids没有匹配的成分阵列（成分未知）所以对于这个披萨，我想将成分设置为null并获得下一个阵列：

新阵列PizzaAndIngredients：

0 => array:5 [▼
    "pizza_cid" => 11
    "pizza_name" => "Hawaï"
    "ingredient_one" => "Ananas"
    "ingredient_two" => "Onion"
    "ingredient_three" => "Ham"
]
1 => array:5 [▼
    "pizza_id" => 12
    "pizza_name" => "Tonno"
    "ingredient_one" => "Tuna"
    "ingredient_two" => "Onion"
    "ingredient_three" => null
]
2 => array:5 [▼
    "pizza_id" => 13
    "pizza_name" => "Surprise"
    "ingredient_one" => null
    "ingredient_two" => null
    "ingredient_three" => null
]

我一直在摆弄array_merge，foreach等，但无法获得数组。另一种方法是构建一个新的查询和左连接比萨饼和成分，但在现实生活中，数组要复杂得多，这意味着要复制大量代码。

我希望能够更有效地合并两个多维阵列的解决方案。

我的最后一次尝试是：

$PizzaAndIngredients = array();
foreach ($pizzas as $key => $values) {
    $PizzaAndIngredients[$key] = array_merge($ingredients, $values);
}

Answer 1

从查询结果中获取行时，您可以将数组键设置为pizza_id，或者按pizza_id重新索引它们：

$pizza       = array_column($pizza, null, 'pizza_id');
$ingredients = array_column($ingredients, null, 'pizza_id');

然后创建一个null的默认数组，以便在$ingredients不存在时使用，然后将$ingredients值与$pizza值合并：< / p>

//get an ingredient array
$temp    = reset($ingredients);
//combine keys and an array of nulls
$default = array_combine(array_keys($temp),
                         array_fill(0, count($temp), null));

foreach($pizza as $id => $p_values) {
    //check if $ingredients[$id] exists, if not use the default
    $i_values    = isset($ingredients[$id]) ? $ingredients[$id] : $default;
    //you can also use just $result[] if you don't need the pizza_id as key
    $result[$id] = array_merge($i_values, $p_values); 
}

合并具有公共ID的多维数组

1 个答案: