Mysql限制，但添加了更多行

Question

我有这张桌子：

name   | age
John   | 35
Amanda | 34
Jane   | 34
Jack   | 34
Craig  | 32
Jason  | 32
Phil   | 32
Kris   | 32
Tyler  | 25
Harry  | 25
Duke   | 24

我想按年龄desc订购并选择前五行。但如果有更多的人与第5行的年龄相同，我也希望他们在我的结果中。类似于：（SELECT * FROM people ORDER BY age DESC LIMIT 0, 5 as W) UNION (SELECT * FROM people WHERE age = W[4].age）

所以上面例子的结果是：

John   | 35
Amanda | 34
Jane   | 34
Jack   | 34
Craig  | 32
Jason  | 32
Phil   | 32
Kris   | 32

• John，Amanda，Jane，Jack，Craig在结果中，因为有前五个最老的
• Jason，Phil，Kris的结果是因为他们与最后一排的年龄相同

有什么方法可以做到吗？非常感谢你

Answer 1

DROP TABLE IF EXISTS my_table;

CREATE TABLE my_table
(name VARCHAR(12) NOT NULL PRIMARY KEY
,age INT NOT NULL)
;

INSERT INTO my_table VALUES
('John'   ,35),
('Amanda' ,34),
('Jane'   ,34),
('Jack'   ,34),
('Craig'  ,32),
('Jason'  ,32),
('Phil'   ,32),
('Kris'   ,32),
('Tyler'  ,25),
('Harry'  ,25),
('Duke'   ,24);

SELECT DISTINCT y.*
           FROM
              ( SELECT *
                  FROM my_table
                 ORDER
                    BY age DESC
                 LIMIT 5
              ) x
           JOIN my_table y
             ON y.age = x.age;
+--------+-----+
| name   | age |
+--------+-----+
| John   |  35 |
| Amanda |  34 |
| Jane   |  34 |
| Jack   |  34 |
| Craig  |  32 |
| Jason  |  32 |
| Phil   |  32 |
| Kris   |  32 |
+--------+-----+

<强> SQL DEMO

Answer 2

你必须使用内部查询来选择前5个年龄，然后反转顺序以选择最后一个。

使用Limit 4, 1跳过前4并选择最后一个

<强> SQL DEMO

SELECT *
FROM (SELECT * 
      FROM people 
      ORDER BY age DESC 
      LIMIT 5 ) as w
UNION 
SELECT * 
FROM people 
WHERE age = (SELECT age
             FROM Table1
             ORDER BY `age` DESC
             LIMIT 4, 1)

<强>输出

Answer 3

如果您尝试

，该怎么办？

SELECT * FROM people
WHERE Age IN (SELECT DISTINCT Age FROM people ORDER BY Age DESC LIMIT 5)