Question

我已经乘以TJM.intMaterialQuantity * TM.monMaterialCost它给出了每个材料项在不同行中的总和。我需要将这4个总计相加并放入一个名为monTotalMaterialCost的新列中。它现在的方式显示monTotalMaterialCost中的每个材质。如何将所有材料的总数合并为一行，以便我可以在一行中看到作业和客户以及总成本？

SELECT
     TJ.intJobID
    ,TC.intCustomerID
    ,TC.strLastName + ', ' + TC.strFirstName AS strCustomerName
    ,(SUM (TJM.intMaterialQuantity) * SUM (TM.monMaterialCost)) AS monTotalMaterialCost


FROM
     TJobs              AS TJ 
    ,TJobCustomers      AS TJC
    ,TCustomers         AS TC 
    ,TJobMaterials      AS TJM
    ,TMaterials         AS TM 

WHERE
        TJ.intJobID         =   TJC.intJobID
    AND TJC.intCustomerID   =   TC.intCustomerID
    AND TJM.intMaterialID   =   TM.intMaterialID
    AND TJM.intJobID        =   TJ.intJobID
    AND TJ.intJobID          = 1

GROUP BY
     TJ.intJobID
    ,TC.intCustomerID
    ,TC.strLastName + ', ' + TC.strFirstName 
    ,TJM.intMaterialQuantity
    ,TM.monMaterialCost

示例输入

--Insert into TMaterials
INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 1, 'Nails', '4.99' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 2, 'Drywall per 32 sqft', '12.99' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 3, '2 x 4', '1.89' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 4, 'Paint per gallon', '32.00' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 5, 'Tile per sqft', '4.99' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 6, 'Copper Water 10ft line', '6.99' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 7, 'Screws', '4.99' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 8, 'Shingles', '40.99' )

INSERT INTO TMaterials ( intMaterialID, strMaterials, monMaterialCost )
VALUES  ( 9, 'Tar Paper per sqft', '1.99' )

 --Insert into TJobMaterials

 --Materials for Job 1 Customer 1
 INSERT INTO TJobMaterials ( intJobID, intMaterialID, intMaterialQuantity )
 VALUES (1, 1, 50 )

 INSERT INTO TJobMaterials ( intJobID, intMaterialID, intMaterialQuantity )
 VALUES (1, 2, 20 )

 INSERT INTO TJobMaterials ( intJobID, intMaterialID, intMaterialQuantity )
  VALUES    (1, 3, 20 )

 INSERT INTO TJobMaterials ( intJobID, intMaterialID, intMaterialQuantity )
 VALUES (1, 4, 5 )

 INSERT INTO TJobMaterials ( intJobID, intMaterialID, intMaterialQuantity )
 VALUES (1, 5, 35 )

 /*
Output I'm Getting

intJobID    strJobDescription    intJobStatusID    strJobStatus    monTotalMaterialCost
   1          Kitchen Remodel           3            Complete           160.00
   1          Kitchen Remodel           3            Complete           37.80
   1          Kitchen Remodel           3            Complete           259.80
   1          Kitchen Remodel           3            Complete           174.65
   1          Kitchen Remodel           3            Complete           249.50

   Output Wanted

   intJobID    strJobDescription    intJobStatusID    strJobStatus    monTotalMaterialCost
      1         Kitchen Remodel          3              Complete            881.75

      I need the total of all 5 outputs into one final total into monTotalMaterialCost

* /

所需的输出： intJobID = 1 strJobDescription = Kitchen Remodel strJobStatus = Complete monTotalMaterialCost = 881.75

我得到了什么： intJobID = 1 strJobDescription = Kitchen Remodel strJobStatus = Complete monTotalMaterialCost = 7391.80

发生了什么：我有5种不同的材料来自TJM.intMaterialQuantity。每行中的每个值为50,20,20,5,35然后我对TM.monMaterialCost中的每种材料有5种不同的成本，这些值以相同的顺序匹配4.99,12.99,1.89,32.00,4.99。我得到了50 + 20 + 20 + 5 + 35 = 130和4.99 + 12.99 + 1.89 + 32.00 + 4.99 = 56.86所以我得到了最终的等式130 * 56.86 = 7,391.80。

我需要的是50 * 4.99 = 249.50,20 * 12.99 = 259.80,20 * 1.89 = 37.80,5 * 32.00 = 160,35 * 4.99 = 174.65我需要将所有这些总数加在一起以获得总金额用于工作的材料共计881.75。

我希望这有助于更好地理解我的问题。

我已经弄清楚了。我已经为未来的问题发布了正确答案：

SELECT
 TJ.intJobID
,TJ.strJobDescription
,TJ.intJobStatusID
,TJS.strJobStatus
, SUM (TJM.intMaterialQuantity * TM.monMaterialCost) AS monTotalMaterialCost


FROM TJobs AS TJ    
        join TJobMaterials AS TJM on TJM.intJobID = TJ.intJobID
        join TMaterials AS TM on TJM.intMaterialID = TM.intMaterialID
        join TJobStatus AS TJS on TJ.intJobStatusID = TJS.intJobStatusID

GROUP BY
 TJ.intJobID
,TJ.strJobDescription
,TJ.intJobStatusID
,TJS.strJobStatus

Answer 1

你真的应该停止使用过时的ANSI-89样式连接。 ANSI-92风格的连接已经存在了25年。它们更容易阅读并防止出现大量意外错误。

Bad habits to kick : using old-style JOINs

查询的后半部分看起来像这样。

FROM TJobs AS TJ 
join TJobCustomers AS TJC on TJ.intJobID = TJC.intJobID
join TCustomers AS TC on TJC.intCustomerID = TC.intCustomerID
join TJobMaterials AS TJM on TJM.intJobID = TJ.intJobID
join TMaterials AS TM on TJM.intMaterialID = TM.intMaterialID
WHERE TJ.intJobID = 1

如何将列总数添加到一起

1 个答案: