我是python的新手,并尝试用类和对象编写程序。以下是我的代码:
class Animal:
__name = ""
__height = 0
__weight = 0
__sound = 0
# define a constructor and pass arguments
def __init__(self, name, height, weight, sound):
self.__name = name
self.__height = height
self.__weight = weight
self.__sound = sound
# set and get functions for name
def set_name(self, name):
self.__name = name
def get_name(self):
return self.__name
# set and get functions for height
def set_height(self, height):
self.__height = height
def get_height(self):
return str(self.__height)
# set and get functions for weight
def set_weight(self, weight):
self.__weight = weight
def get_weight(self):
return str(self.__weight)
# set and get functions for sound
def set_sound(self, sound):
self.__sound = sound
def get_sound(self):
return self.__sound
def get_type(self):
print("Animal")
def toString(self):
return "{} is {} cm tall and {} kg and say {}".format(self.__name, self.__height, self.__weight, self.__sound)
# create an object call cat of type Animal
cat = Animal('Whiskers', 33, 10, 'Meow')
print(cat.toString())
当我运行程序时,它给出了一个错误,即对象不带参数。但我已经在类的构造函数中描述了参数。请帮助。
答案 0 :(得分:5)
确保Animal的所有功能都正确缩进。他们需要在Animal类中
答案 1 :(得分:3)
正如其他人所提到的,__init__
方法需要在Animal类中缩进,以便将其视为构造函数。
但是,这样做之后要小心。现在声明__name
,__height
,__weight
和__sound
的方式,它们是静态类变量。但是,在__init__
中(通过在变量前添加前缀self.
),您将使用名称变量名称重新声明实例变量。