有人可以帮助我如何编写for循环来迭代所有这些区域节点并获取只有类导致的文本？
<zones count="13">
<zone type="RECT" flags="4099" class="Headline" num="1">
<zrect unit="pix">0,1097,2173,1303</zrect>
<ztext type="XML" textformat="XML">
<REGION>
<PARAGRAPH>
<LINE>
<WORD Rect="27,933,272,1067">ma</WORD>
<BLANK/>
<WORD Rect="325,933,820,1096">ekdum</WORD>
<BLANK/>
<WORD Rect="877,933,982,1065">gyani</WORD>
<BLANK/>
<WORD Rect="1040,933,1829,1096">chu</WORD>
<BLANK/>
</LINE>
</PARAGRAPH>
</REGION>
</ztext>
<source/>
</zone>
<zone type="RECT" flags="4099" class="Author" num="2">
<zrect unit="pix">0,1326,324,1372</zrect>
<ztext type="XML" textformat="XML">
<REGION>
<PARAGRAPH>
<LINE>
<WORD Rect="4,1126,44,1158">By</WORD>
<BLANK/>
<WORD Rect="54,1126,131,1151">Sano</WORD>
<BLANK/>
<WORD Rect="145,1126,272,1151">shrest</WORD>
<BLANK/>
</LINE>
</PARAGRAPH>
</REGION>
</ztext>
<source/>
</zone>
<zone type="RECT" flags="4099" class="Lead" num="3">
<zrect unit="pix">0,1384,475,1584</zrect>
<ztext type="XML" textformat="XML">
<REGION>
<PARAGRAPH>
<LINE>
<WORD Rect="5,1174,42,1192">Dherai</WORD>
<BLANK/>
<WORD Rect="55,1178,118,1198">years</WORD>
<BLANK/>
<WORD Rect="130,1178,166,1192">dekhin</WORD>
<BLANK/>
<WORD Rect="179,1174,263,1192">gadi</WORD>
<BLANK/>
<WORD Rect="277,1174,331,1192">banaune</WORD>
<BLANK/>
<WORD Rect="344,1174,399,1192">manche</WORD>
<BLANK/>
</LINE>
<LINE>
<WORD Rect="4,1203,91,1226">haru</WORD>
<BLANK/>
<WORD Rect="115,1203,147,1221">mehanat</WORD>
<BLANK/>
<WORD Rect="172,1207,218,1221">gardai</WORD>
<BLANK/>
<WORD Rect="241,1203,399,1226">chan</WORD>
<BLANK/>
</LINE>
<LINE>
<WORD Rect="3,1236,63,1255">ramro</WORD>
<BLANK/>
<WORD Rect="80,1233,102,1250">gadi</WORD>
<BLANK/>
<WORD Rect="119,1231,214,1255">nirman</WORD>
<BLANK/>
<WORD Rect="232,1231,323,1254">garna</WORD>
<BLANK/>
<WORD Rect="341,1236,400,1250">lai</WORD>
<BLANK/>
</LINE>
</PARAGRAPH>
</REGION>
</ztext>
<source/>
</zone>
<zone type="RECT" flags="4099" class="Paragraph" num="4">
<zrect unit="pix">0,1596,478,2249</zrect>
<ztext type="XML" textformat="XML">
<REGION>
<PARAGRAPH>
<LINE>
<WORD Rect="28,1352,74,1366">Ramro</WORD>
<BLANK/>
<WORD Rect="82,1356,114,1366">gadi</WORD>
<BLANK/>
<WORD Rect="122,1356,151,1369">are,</WORD>
<BLANK/>
<WORD Rect="158,1352,179,1366">for</WORD>
<BLANK/>
<WORD Rect="186,1356,196,1366">a</WORD>
<BLANK/>
<WORD Rect="202,1352,254,1369">variety</WORD>
<BLANK/>
<WORD Rect="262,1352,274,1366">of</WORD>
<BLANK/>
<WORD Rect="283,1356,348,1368">reasons,</WORD>
<BLANK/>
<WORD Rect="356,1352,400,1369">ramro</WORD>
<BLANK/>
</LINE>
</PARAGRAPH>
</REGION>
</ztext>
<source/>
</zone>
我能够获得所有区域的文本，但不能特别使用属性class =＆＃34; Lead＆＃34;
答案 0 :(得分：0)
W3学校的例子。 资料来源：http://www.w3schools.com/xml/xpath_syntax.asp
这是xml：
<bookstore>
<book category="cooking">
<title lang="en">Everyday Italian</title>
<author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="children">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="web">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="web" cover="paperback">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>
将提取您希望的节点的Javascript函数。请注意，我们使用//book[@category='web']来获取具有 attribute = value 对的所有节点。同样，您可以//zone[@class='Lead']。
<html>
<body>
<p id="demo"></p>
<script>
function showResult(xml) {
var txt = "";
path = "//book[@category='web']/title";
if (xml.evaluate) {
var nodes = xml.evaluate(path, xml, null, XPathResult.ANY_TYPE, null);
var result = nodes.iterateNext();
while (result) {
txt += result.childNodes[0].nodeValue + "<br>";
result = nodes.iterateNext();
}
document.getElementById("demo").innerHTML = txt;
}
</script>
</body>
</html>