Question

我有以下脚本。它正确地从文本文件

返回整数值（文件ID）的第一个实例

#!/bin/bash

#create file list
mtp-files > file_list.txt
echo "Hello World"

#retrieve File ID from file list
id=$(awk -F'[ \t]*:[ \t]*' '$1 == "File ID"{print $2; exit}' file_list.txt)

echo "$id"

但是我需要一个包含所有文件ID整数值而不重复的数组。例如，如果以下是我的file_list.txt，我的脚本应该返回一个包含8,9,10

的数组

libmtp version: 1.1.10

mtp-files: Successfully connected
Android device detected, assigning default bug flags
Listing File Information on Device with name: LGE 360 CAM MTP Device
File ID: 8
   Filename: 20161212_095355.jpg
   File size 625762 (0x0000000000098C62) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 9
   Filename: 20161212_095416.jpg
   File size 602264 (0x0000000000093098) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 10
   Filename: 20161212_095520.jpg
   File size 642770 (0x000000000009CED2) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 8
   Filename: 20161212_095355.jpg
   File size 625762 (0x0000000000098C62) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 9
   Filename: 20161212_095416.jpg
   File size 602264 (0x0000000000093098) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 10
   Filename: 20161212_095520.jpg
   File size 642770 (0x000000000009CED2) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 8
   Filename: 20161212_095355.jpg
   File size 625762 (0x0000000000098C62) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 9
   Filename: 20161212_095416.jpg
   File size 602264 (0x0000000000093098) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
File ID: 10
   Filename: 20161212_095520.jpg
   File size 642770 (0x000000000009CED2) bytes
   Parent ID: 2
   Storage ID: 0x00010001
   Filetype: JPEG file
OK.

Answer 1

这个awk应该可以解决问题。您不需要第三方工具sort和uniq来删除重复项，而awk可以自行执行此操作。

awk -F'[: ]' '/^File ID/{seen[$2]++;}END{ for (i in seen) print i}' file_list.txt

Answer 2

这应该可以解决问题

id=$(awk -F'[ \t]*:[ \t]*' '$1 == "File ID"{print $2; exit}' file_list.txt | sort | uniq)

Answer 3

如果您只想获取ID，可以像这样减少awk命令：

awk '/File ID/ { print $3 }' file_list.txt | sort | uniq

您仍然需要使用sort和uniq命令才能删除任何重复的结果。

整个命令是：

array_of_ids=($(awk '/File ID/ { print $3 }' file_list.txt | sort | uniq))
echo ${array_of_ids[@]}
10 8 9

echo ${array_of_ids[0]}
10
echo ${array_of_ids[1]}
8
echo ${array_of_ids[2]}
9

**命令周围的“额外”（“和”）“确保您创建一个bash数组。

Bash＆gt;从文本文件中检索整数值数组而不重复

3 个答案: