Question

Web服务返回以下嵌套的json对象：

{"age":"21-24","gender":"Male","location":"San Francisco, CA","influencer score":"70-79","interests":{"Entertainment":{"Celebrities":{"Megan Fox":{},"Michael Jackson":{}},},"Social Networks & Online Communities":{"Web Personalization": {},"Journals & Personal Sites": {},},"Sports":{"Basketball":{}},},"education":"Completed Graduate School","occupation":"Professional/Technical","children":"No","household_income":"75k-100k","marital_status":"Single","home_owner_status":"Rent"}

我只是想在不指定属性名的情况下遍历此对象，我尝试了以下代码：

for (var data in json_data) {
    alert("Key:" + data + " Values:" + json_data[data]);
}

然而，如果它是一个嵌套值，它会将值打印为[object Object]，有没有办法让迭代更深入嵌套值？

Answer 1

试试这个：

function iter(obj) {
  for (var key in obj) {
    if (typeof(obj[key]) == 'object') {
      iter(obj[key]);
    } else {
      alert("Key: " + key + " Values: " + obj[key]);
    }
  }
}

BB：添加+以防止错误。

Answer 2

你可以递归地做到这一点。

function alertobjectKeys(data) {
  for (var key in data) {
    if (typeof(data[key]) == "object" && data[key] != null) {
      alertobjectKeys(data[key]);
    } else {
      alert("Key:" + key + " Values:" + data[key]);
    }
  }
}

Answer 3

您始终可以创建递归函数：

function alertObj(obj) {
    for (var data in obj) {
        if(typeof(obj[data]) === "object")
            alertObj(obj[data]);
        else
            alert("Key:" + data + " Values:" + obj[data]);
    }
}

只要你不担心递归过多（你可能不需要使用JSON对象）。

您也可以使用队列或堆栈（数组）结构执行此操作：

function alertObj_queue(obj) { // Breadth-first
    var arrPrint = [{key:"Object", data:obj}]; // Initialize array with original object

    for(var i = 0; i < arrPrint.length; i++) {
        if(typeof(arrPrint[i].data) === "object") {
            for(var k in arrPrint[i].data) { // Add each to end of array
                arrPrint.push({key: k, data: arrPrint[i].data[k]});
            }
            alert("Object key: " + arrPrint[i].key);
        } else {
            alert("Key:" + arrPrint[i].key + " Values:" + arrPrint[i].data);
        }
    }
}

function alertObj_stack(obj) { // Depth-first
    var arrPrint = [{key:"Object", data:obj}]; // Initialize array with original object

    while(arrPrint.length) {
        var o = arrPrint.pop();
        if(typeof(o.data) === "object") {
            for(var k in o.data) { // Add each to end of array
                arrPrint.push({key: k, data: o.data[k]});
            }
            alert("Object key: " + o.key);
        } else {
            alert("Key:" + o.key + " Values:" + o.data);
        }       
    }
}

Answer 4

这当然需要递归

(function(obj) {
  for (var key in obj) if (obj.hasOwnProperty(key)) {
    if (typeof obj[key] == 'object' && obj[key] !== null)
      arguments.callee(obj[key]);
    else 
      alert("Key: " + key + " Values: " + obj[key]);
  }
)(json_data));

Answer 5

function recursiveParse(variable) { 
    for (var key in variable) {
        if ((is_object(variable[key])) || (is_array(variable[key]))) {
            recursiveParse(variable[key]);
        } else {
            // Process variable here
        }
    }
}

然后只使用参数为json数据调用该函数，它将递归地解析剩余的对象和数组。

Answer 6

我猜你的请求（假设它是Ajax）你没有指定dataType作为'json'返回。

在不使用变量名的情况下打印嵌套的JSON

6 个答案: